Meida D

07 November 2023 00:50

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Meida D

07 November 2023 00:50

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Jawaban terverifikasi

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Jayahadi S

07 November 2023 02:04

Jawaban terverifikasi

<p>a.&nbsp;&nbsp;&nbsp; C<sub>6</sub>H<sub>6</sub>(l)&nbsp; O<sub>2</sub>(g)&nbsp;&nbsp; --&gt;&nbsp; H<sub>2</sub>O(l) +&nbsp; CO<sub>2</sub>(g)&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp;&nbsp;<strong>2 </strong>C<sub>6</sub>H<sub>6</sub>(l)&nbsp; <strong>15</strong> O<sub>2</sub>(g)&nbsp;&nbsp; --&gt;&nbsp; <strong>6</strong> H<sub>2</sub>O(l) +&nbsp; <strong>12</strong> CO<sub>2</sub>(g)&nbsp;</p><p>b.&nbsp;&nbsp;&nbsp; SiO<sub>2</sub>(s)&nbsp; +&nbsp; C(s)&nbsp;&nbsp; --&gt;&nbsp;&nbsp; Si(s)&nbsp; +&nbsp; CO(g)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; SiO<sub>2</sub>(s)&nbsp; +&nbsp; <strong>2 </strong>C(s)&nbsp;&nbsp; --&gt;&nbsp;&nbsp; Si(s)&nbsp; +&nbsp; <strong>2</strong> CO(g)</p><p>c.&nbsp;&nbsp;&nbsp;&nbsp; PH<sub>3</sub>(s)&nbsp; +&nbsp; O<sub>2</sub>(g) &nbsp; --&gt;&nbsp;&nbsp; P<sub>4</sub>O<sub>10</sub>(s)&nbsp; +&nbsp; H<sub>2</sub>O(l)</p><p>&nbsp; &nbsp; &nbsp; &nbsp;<strong>4</strong> PH<sub>3</sub>(s)&nbsp; + <strong>8</strong> O<sub>2</sub>(g) &nbsp; --&gt;&nbsp;&nbsp; P<sub>4</sub>O<sub>10</sub>(s)&nbsp; +&nbsp; <strong>6</strong> H<sub>2</sub>O(l)</p><p>d.&nbsp;&nbsp;&nbsp; CaO(s)&nbsp; +&nbsp; NH<sub>4</sub>Cl(s)&nbsp; &nbsp;--&gt;&nbsp;&nbsp; NH<sub>3</sub>(g)&nbsp; +&nbsp; H<sub>2</sub>O(g)&nbsp; +&nbsp; CaCl<sub>2</sub>(s)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; CaO(s)&nbsp; +&nbsp; <strong>2</strong> NH<sub>4</sub>Cl(s)&nbsp; --&gt; &nbsp;&nbsp; <strong>2</strong> NH<sub>3</sub>(g)&nbsp; +&nbsp; H<sub>2</sub>O(g)&nbsp; +&nbsp; CaCl<sub>2</sub>(s)</p><p>e.&nbsp;&nbsp;&nbsp; Na<sub>2</sub>CO<sub>3</sub>(s)&nbsp; +&nbsp; HCl(aq)&nbsp;&nbsp; --&gt;&nbsp;&nbsp; NaCl(aq)&nbsp; +&nbsp; H<sub>2</sub>O(l)&nbsp; +&nbsp; CO<sub>2</sub>(g)</p><p>&nbsp; &nbsp; &nbsp; &nbsp;Na<sub>2</sub>CO<sub>3</sub>(s)&nbsp; +&nbsp; <strong>2</strong> HCl(aq)&nbsp;&nbsp; --&gt;&nbsp;&nbsp; <strong>2</strong> NaCl(aq)&nbsp; +&nbsp; H<sub>2</sub>O(l)&nbsp; +&nbsp; CO<sub>2</sub>(g)</p>

a.    C6H6(l)  O2(g)   -->  H2O(l) +  CO2(g) 

        2 C6H6(l)  15 O2(g)   -->  6 H2O(l) +  12 CO2(g) 

b.    SiO2(s)  +  C(s)   -->   Si(s)  +  CO(g)

        SiO2(s)  +  2 C(s)   -->   Si(s)  +  2 CO(g)

c.     PH3(s)  +  O2(g)   -->   P4O10(s)  +  H2O(l)

       4 PH3(s)  + 8 O2(g)   -->   P4O10(s)  +  6 H2O(l)

d.    CaO(s)  +  NH4Cl(s)   -->   NH3(g)  +  H2O(g)  +  CaCl2(s)

        CaO(s)  +  2 NH4Cl(s)  -->    2 NH3(g)  +  H2O(g)  +  CaCl2(s)

e.    Na2CO3(s)  +  HCl(aq)   -->   NaCl(aq)  +  H2O(l)  +  CO2(g)

       Na2CO3(s)  +  2 HCl(aq)   -->   2 NaCl(aq)  +  H2O(l)  +  CO2(g)


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Rahma P

30 Januari 2024 01:12

Jawaban terverifikasi

<p>C<sub>6</sub>H<sub>6</sub> + O<sub>2&nbsp;</sub> ----&gt; H<sub>2</sub>O + CO<sub>2</sub></p><p>= disetarakan menjadi &nbsp;C<sub>6</sub>H<sub>6</sub> + <strong>15/2</strong> O<sub>2</sub> ----&gt; <strong>3</strong>H<sub>2</sub>O + <strong>6</strong>CO<sub>2</sub></p><p><sub>SiO2 + C ------&gt; Si + CO</sub></p><p><sub>= disetarakan menjadi SiO2 + </sub><strong><sub>2</sub></strong><sub>C -------&gt; Si + </sub><strong><sub>2</sub></strong><sub>CO</sub></p><p>&nbsp;</p>

C6H6 + O ----> H2O + CO2

= disetarakan menjadi  C6H6 + 15/2 O2 ----> 3H2O + 6CO2

SiO2 + C ------> Si + CO

= disetarakan menjadi SiO2 + 2C -------> Si + 2CO

 


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