Venusa N

20 Februari 2024 01:53

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Venusa N

20 Februari 2024 01:53

Pertanyaan

Bangun ruang terdiri dari tabung dan kerucut, disimpan bertumpuk. Tutup tabung dan alas kerucut berimpit. Tinggi kerucut 24cm. Tinggi 1/3 dari tinggi kerucut. Luas alas nya 154cm. Ditanyakan a. Volume seluruh bangun ruang tersebut b. Luas seluruh permukaan tersebut

Bangun ruang terdiri dari tabung dan kerucut, disimpan bertumpuk. Tutup tabung dan alas kerucut berimpit. Tinggi kerucut 24cm. Tinggi 1/3 dari tinggi kerucut. Luas alas nya 154cm. Ditanyakan 

a. Volume seluruh bangun ruang tersebut

b. Luas seluruh permukaan tersebut

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Jawaban terverifikasi

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000000000000000000000000d3649aad53caf2c821021249ad0aeaf82558fe28f686b5ae496cd97ef79a176bf4 0

20 Februari 2024 23:52

Jawaban terverifikasi

<p>Diketahui :&nbsp;</p><p>Tinggi kerucut = 24 cm</p><p>Tinggi tabung = ⅓ × 24 = 8 cm</p><p>Luas alas = 154 cm</p><p>&nbsp;</p><p>Ditanya :</p><p>a. Volume total = ....</p><p>b. Luas seluruh permukaan = ...</p><p>&nbsp;</p><p>Luas lingkaran = Luas alas</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 𝞹 r² = 154</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 22/7 × r² = 154</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;r² = 154 × 7/22&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;r² = 49</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; r = √49 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 7 cm</p><p>&nbsp;</p><p>Sisi kerucut = √r² + t²</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = √7² + 24²</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = √49 + 576</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = √625 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 25 cm</p><p>&nbsp;</p><p>a. &nbsp;Volume total = volume kerucut &nbsp;+ volume tabung</p><p>&nbsp; &nbsp; &nbsp; V total = ⅓ 𝞹 r² t + 𝞹 r² t</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; =( ⅓ × 22/7 × 7 × 7 × 24 ) + (22/7 × 7 × 7 × 8)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 1.234 + 1.234 &nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 2.468 cm³</p><p>&nbsp;</p><p>b. Luas total = Luas selimut kerucut + Luas selimut tabung + &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Luas alas&nbsp;</p><p>&nbsp; &nbsp; &nbsp;L total = 𝞹 r s + 2 𝞹 r t + 𝞹 r²</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= (22/7 × 7 × 25 ) + (2 × 22/7 × 7 × 8) + 154</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 550 + 352 + 154</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 1.056 cm²</p>

Diketahui : 

Tinggi kerucut = 24 cm

Tinggi tabung = ⅓ × 24 = 8 cm

Luas alas = 154 cm

 

Ditanya :

a. Volume total = ....

b. Luas seluruh permukaan = ...

 

Luas lingkaran = Luas alas

                      𝞹 r² = 154

            22/7 × r² = 154

                         r² = 154 × 7/22 

                         r² = 49

                          r = √49           = 7 cm

 

Sisi kerucut = √r² + t²

                          = √7² + 24²

                          = √49 + 576

                          = √625           = 25 cm

 

a.  Volume total = volume kerucut  + volume tabung

      V total = ⅓ 𝞹 r² t + 𝞹 r² t

                    =( ⅓ × 22/7 × 7 × 7 × 24 ) + (22/7 × 7 × 7 × 8)

                    = 1.234 + 1.234  

                    = 2.468 cm³

 

b. Luas total = Luas selimut kerucut + Luas selimut tabung +                                  Luas alas 

     L total = 𝞹 r s + 2 𝞹 r t + 𝞹 r²

                   = (22/7 × 7 × 25 ) + (2 × 22/7 × 7 × 8) + 154

                   = 550 + 352 + 154

                   = 1.056 cm²


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