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Zat berikut yang memiliki hasil elektrolisis yang sama di katode dengan larutan  menggunakan elektrode inert adalah

Pertanyaan

Zat berikut yang memiliki hasil elektrolisis yang sama di katode dengan larutan begin mathsize 14px style Na subscript 2 S O subscript 4 end style menggunakan elektrode inert adalah undefined 

  1. begin mathsize 14px style larutan space Fe S O subscript 4 end style 

  2. begin mathsize 14px style lelehan space Na Cl end style 

  3. size 14px larutan size 14px space Mn C O subscript size 14px 3 

  4. size 14px larutan size 14px space Cu S O subscript size 14px 4 

  5. begin mathsize 14px style lelehan space K Cl end style 

Pembahasan Soal:

Reaksi elektrolisis di katode pada larutan begin mathsize 14px style Na subscript 2 S O subscript 4 end style terbentuk begin mathsize 14px style gas space H subscript 2 space dan space O H to the power of minus sign end style.

begin mathsize 14px style space space space space space space space space space space space Na subscript 2 S O subscript 4 subscript open parentheses italic a italic q close parentheses end subscript yields 2 Na to the power of plus sign plus S O subscript 4 to the power of 2 minus sign end exponent Katode space colon space 2 H subscript 2 O and 2 e yields 2 O H to the power of minus sign and H subscript 2 end style

Reaksi elektrolisis di katode pada masing - masing zat:

begin mathsize 14px style A right parenthesis space space space space space space space space space Fe S O subscript 4 subscript left parenthesis italic a italic q right parenthesis end subscript end subscript yields Fe to the power of 2 plus sign and S O subscript 4 to the power of 2 minus sign end exponent Katode space colon space Fe to the power of 2 plus sign and 2 e yields Fe  B right parenthesis space space space space space space space space space space space Na Cl subscript left parenthesis italic l right parenthesis end subscript yields Na to the power of plus sign and Cl to the power of minus sign Katode space colon space Na to the power of plus sign and e yields Na  C right parenthesis space space space space space space space space Mn C O subscript 3 subscript left parenthesis italic a italic q right parenthesis end subscript end subscript yields Mn to the power of 2 plus sign and C O subscript 3 to the power of 2 minus sign end exponent Katode space colon space 2 H subscript 2 O and 2 e yields 2 O H to the power of minus sign and H subscript 2  D right parenthesis space space space space space space space space Cu S O subscript 4 subscript left parenthesis italic a italic q right parenthesis end subscript end subscript yields Cu to the power of 2 plus sign and S O subscript 4 to the power of 2 minus sign end exponent Katode space colon space Cu to the power of 2 plus sign and 2 e yields Cu  E right parenthesis space space space space space space space space space space space space K Cl subscript left parenthesis italic l right parenthesis end subscript yields K to the power of plus sign and Cl to the power of minus sign Katode space colon space K to the power of plus sign and e yields K end style

Zat yang memiliki hasil elektrolisis yang sama di katode dengan larutan undefined  adalah begin mathsize 14px style Mn C O subscript 3 end style.

Jadi, jawaban yang benar adalah C.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 02 Februari 2021

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