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Untuk menyelesaikan soal berikut lihat Ar unsur pada tabel periodik. Tentukan jumlah atom Fe, S, dan O pada 4 gram besi(III) sulfat, .

Pertanyaan

Untuk menyelesaikan soal berikut lihat Ar unsur pada tabel periodik.

Tentukan jumlah atom Fe, S, dan O pada 4 gram besi(III) sulfat, Fe subscript 2 open parentheses S O subscript 4 close parentheses subscript 3.

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell Mr space Fe subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 end cell equals cell left parenthesis 2 xAr space Fe right parenthesis plus left parenthesis 3 xAr space S right parenthesis plus left parenthesis 12 xAr space O right parenthesis end cell row blank equals cell left parenthesis 2 x 56 right parenthesis plus left parenthesis 3 x 32 right parenthesis plus left parenthesis 12 x 16 right parenthesis end cell row blank equals cell 112 plus 96 plus 192 end cell row blank equals cell 400 space g forward slash mol end cell row cell mol space Fe subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 end cell equals cell fraction numerator massa space Fe subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 over denominator Mr space Fe subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 end fraction end cell row blank equals cell fraction numerator 4 space g over denominator 400 space g forward slash mol end fraction end cell row blank equals cell 0 comma 01 space mol end cell row blank blank blank row cell Jumlah space atom end cell equals cell mol space x space N end cell row cell bilangan space Avogadro open parentheses N close parentheses end cell equals cell 6 comma 02 x 10 to the power of 23 space atom point mol to the power of negative sign 1 end exponent end cell row blank blank blank row cell Jumlah space atom space Fe end cell equals cell 2 space x space mol space Fe subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 space x space 6 comma 02 x 10 to the power of 23 end cell row blank equals cell 2 space x space 0 comma 01 space x space 6 comma 02 x 10 to the power of 23 end cell row blank equals cell 0 comma 1204 x 10 to the power of 23 space atom end cell row blank equals cell 1 comma 204 space x space 10 to the power of 22 space atom end cell row blank blank blank row cell Jumlah space atom space S end cell equals cell 3 space x space mol space Fe subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 space x space 6 comma 02 x 10 to the power of 23 end cell row blank equals cell 3 space x space 0 comma 01 space x space 6 comma 02 x 10 to the power of 23 end cell row blank equals cell 0 comma 1806 x 10 to the power of 23 space atom end cell row blank equals cell 1 comma 806 space x space 10 to the power of 22 space atom end cell row blank blank blank row cell Jumlah space atom space O end cell equals cell 12 space x space mol space Fe subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 space x space 6 comma 02 x 10 to the power of 23 end cell row blank equals cell 12 space x space 0 comma 01 space x space 6 comma 02 x 10 to the power of 23 end cell row blank equals cell 0 comma 7224 x 10 to the power of 23 space atom end cell row blank equals cell 7 comma 224 space x space 10 to the power of 22 space atom end cell end table

 

Jadi, jawaban sesuai dengan uraian di atas.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 04 Juni 2021

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