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Untuk menyelesaikan soal berikut lihat Ar unsur pada tabel periodik. Tentukan jumlah atom N, H, S, dan O pada 66 gram amonium sulfat, .

Pertanyaan

Untuk menyelesaikan soal berikut lihat Ar unsur pada tabel periodik.

Tentukan jumlah atom N, H, S, dan O pada 66 gram amonium sulfat, open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 end subscript.

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell Mr space open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 end subscript end cell equals cell left parenthesis 2 xAr space N right parenthesis plus left parenthesis 8 xAr space H right parenthesis plus Ar space S plus left parenthesis 4 xAr space O right parenthesis end cell row blank equals cell left parenthesis 2 x 14 right parenthesis plus left parenthesis 8 x 1 right parenthesis plus 32 plus left parenthesis 4 x 16 right parenthesis end cell row blank equals cell 28 plus 8 plus 32 plus 64 end cell row blank equals cell 132 space g forward slash mol end cell row blank blank blank row cell mol space open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 end cell equals cell fraction numerator massa space open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 over denominator Mr space open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 end fraction end cell row blank equals cell fraction numerator 66 space g over denominator 132 space g forward slash mol end fraction end cell row blank equals cell 0 comma 5 space mol end cell row blank blank blank row cell jumlah space atom end cell equals cell mol space x space open parentheses 6 comma 02 x 10 to the power of 23 space atom point mol to the power of negative sign 1 end exponent close parentheses end cell row blank blank blank row cell Jumlah space atom space N end cell equals cell 2 xmol space open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 x open parentheses 6 comma 02 x 10 to the power of 23 close parentheses end cell row blank equals cell 2 x 0 comma 5 x space open parentheses 6 comma 02 x 10 to the power of 23 close parentheses end cell row blank equals cell 6 comma 02 x 10 to the power of 23 space atom end cell row blank blank blank row cell Jumlah space atom space H end cell equals cell 2 xmol space open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 x open parentheses 6 comma 02 x 10 to the power of 23 close parentheses end cell row blank equals cell 8 x 0 comma 5 x space open parentheses 6 comma 02 x 10 to the power of 23 close parentheses end cell row blank equals cell 24 comma 08 x 10 to the power of 23 space atom end cell row blank equals cell 2 comma 408 x 10 to the power of 22 space atom end cell row blank blank blank row cell Jumlah space atom space S end cell equals cell 1 xmol space open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 x open parentheses 6 comma 02 x 10 to the power of 23 close parentheses end cell row blank equals cell 1 x 0 comma 5 x space open parentheses 6 comma 02 x 10 to the power of 23 close parentheses end cell row blank equals cell 3 comma 01 x 10 to the power of 23 space atom end cell row blank blank blank row cell Jumlah space atom space O end cell equals cell 4 xmol space open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 x open parentheses 6 comma 02 x 10 to the power of 23 close parentheses end cell row blank equals cell 4 x 0 comma 5 x space open parentheses 6 comma 02 x 10 to the power of 23 close parentheses end cell row blank equals cell 12 comma 04 x 10 to the power of 23 space atom end cell row blank equals cell 1 comma 204 x 10 to the power of 22 space atom end cell row blank blank blank row blank blank blank end table

Jadi, jawaban sesuai dengan uraian di atas.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 04 Juni 2021

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