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Untuk membuat larutan penyangga dengan  sebanyak 5...

Untuk membuat larutan penyangga dengan begin mathsize 14px style pH equals 8 minus sign log space 2 end style sebanyak 500 mL, maka volume larutan begin mathsize 14px style N H subscript 4 O H end style 0,2 M dan volume begin mathsize 14px style N H subscript 4 Cl end style 0,1 M yang harus dicampur masing-masing sebanyak .... begin mathsize 14px style left parenthesis K subscript b equals 10 to the power of negative sign 6 end exponent right parenthesis end stylebegin mathsize 14px style space end style

Jawaban:

Larutan penyangga adalah larutan yang dapat mempertahankan harga pH. Campuran larutan begin mathsize 14px style N H subscript 4 O H end style dengan begin mathsize 14px style N H subscript 4 Cl end style akan membentuk larutan penyangga basa.

Untuk membuat larutan penyangga dengan begin mathsize 14px style pH equals 8 minus sign log space 2 end style sebanyak 500 mL, maka volume larutan begin mathsize 14px style N H subscript 4 O H end style 0,2 M dan volume begin mathsize 14px style N H subscript 4 Cl end style 0,1 M yang harus dicampur dapat ditentukan dengan rumus berikut.


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell 8 minus sign log space 2 comma space maka space colon end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 2 cross times 10 to the power of negative sign 8 end exponent end cell row cell open square brackets O H to the power of minus sign close square brackets. open square brackets H to the power of plus sign close square brackets end cell equals cell 10 to the power of negative sign 14 end exponent end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell fraction numerator 10 to the power of negative sign 14 end exponent over denominator 2 cross times 10 to the power of negative sign 8 end exponent end fraction end cell row blank equals cell 5 cross times 10 to the power of negative sign 7 end exponent end cell row blank blank blank row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell K subscript b cross times n subscript basa over n subscript garam end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell K subscript b cross times n subscript N H subscript 4 O H end subscript over n subscript N H subscript 4 Cl end subscript end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell K subscript b cross times open parentheses M point V close parentheses subscript N H subscript 4 O H end subscript over open parentheses M point V close parentheses subscript N H subscript 4 Cl end subscript end cell row cell 5 cross times 10 to the power of negative sign 7 end exponent end cell equals cell 10 to the power of negative sign 6 end exponent cross times fraction numerator 0 comma 2 point V subscript N H subscript 4 O H end subscript over denominator 0 comma 1 point V subscript N H subscript 4 Cl end subscript end fraction end cell row cell fraction numerator 5 cross times 10 to the power of negative sign 7 end exponent over denominator 10 to the power of negative sign 6 end exponent end fraction end cell equals cell fraction numerator 2 point V subscript N H subscript 4 O H end subscript over denominator V subscript N H subscript 4 Cl end subscript end fraction end cell row cell 0 comma 5 end cell equals cell fraction numerator 2 point V subscript N H subscript 4 O H end subscript over denominator V subscript N H subscript 4 Cl end subscript end fraction end cell row cell 1 fourth end cell equals cell V subscript N H subscript 4 O H end subscript over V subscript N H subscript 4 Cl end subscript end cell row cell V subscript N H subscript 4 Cl end subscript end cell equals cell 4 point V subscript N H subscript 4 O H end subscript end cell end table end style


Jika volume total larutan adalah 500 mL, maka :


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript N H subscript 4 O H end subscript end cell equals cell 1 fifth cross times 500 space mL end cell row blank equals cell 100 space mL end cell row blank blank blank row cell V subscript N H subscript 4 Cl end subscript end cell equals cell 4 over 5 cross times 500 space mL end cell row blank equals cell 400 space mL end cell end table end style


Jadi, volume larutan begin mathsize 14px style N H subscript 4 O H end style 0,2 M dan volume begin mathsize 14px style N H subscript 4 Cl end style 0,1 M yang harus dicampur masing-masing sebanyak 100 mL dan 400 mL.space

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