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Tiga roda A, B, dan C dihubungkan dengan tali seperti gambar. Jika roda A berputar sebanyak 240 kali dalam 1 menit, maka kecepatan linier roda C adalah...

  1. 0,448 begin mathsize 12px style straight pi space straight m. straight s to the power of negative 1 end exponent end style

  2. 0,384 begin mathsize 12px style straight pi space straight m. straight s to the power of negative 1 end exponent end style

  3. 0, 348 begin mathsize 12px style straight pi space straight m. straight s to the power of negative 1 end exponent end style

  4. 0,288 begin mathsize 12px style straight pi space straight m. straight s to the power of negative 1 end exponent end style

  5. 0,204 begin mathsize 12px style straight pi space straight m. straight s to the power of negative 1 end exponent end style

R. Anjasmara

Master Teacher

Mahasiswa/Alumni Universitas Riau

Jawaban terverifikasi

Pembahasan

straight R subscript straight A equals space 8 space cm space semicolon space straight R subscript straight B equals space 20 space cm space semicolon space straight R subscript straight C equals space 12 space cm  straight f subscript straight A equals space fraction numerator 240 over denominator 1 space menit end fraction equals space fraction numerator 240 over denominator 60 space straight s end fraction equals space 4 space Hz  straight omega subscript straight A equals space 2 straight pi space straight f subscript straight A equals space 2 straight pi open parentheses 4 close parentheses space equals 8 straight pi space rad divided by straight s  straight v subscript straight C space ?

 

Roda A dan roda B dihubungkan dengan sabuk, maka kecepatan linier roda B akan sama dengan kecepatan linier pada roda A.

straight v subscript straight A equals space straight v subscript straight B  straight omega subscript straight A. straight R subscript straight A space equals space straight omega subscript straight B. straight R subscript straight B  open parentheses 8 straight pi close parentheses open parentheses 8 close parentheses space equals space open parentheses straight omega subscript straight B close parentheses open parentheses 20 close parentheses  straight omega subscript straight B space equals space fraction numerator 64 straight pi over denominator 20 end fraction  straight omega subscript straight B space equals space 3 comma 2 straight pi space rad divided by straight s

 

Roda B dan roda C sepusat. Jadi kecepatan sudut roda B dan roda C sama, sehingga :

straight omega subscript straight B equals space straight omega subscript straight C  straight v subscript straight B over straight R subscript straight B equals space straight v subscript straight C over straight R subscript straight C  3 comma 2 straight pi space space equals space fraction numerator straight v subscript straight C over denominator 0 comma 12 end fraction  straight v subscript straight C equals space 0 comma 384 straight pi space straight m divided by straight s

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