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Terdapat suatu reaksi: 2 NO ( g ) + Br 2 ​ ( g ) → 2 NOBr ( g ) Jika kemolaran NO dinaikkan 2 kali dan kemolaran Br 2 ​ tetap, laju reaksi 4 kalilebih besar. Jika kemolaran NO dan dinaikkan 2 kali, laju reaksi menjadi 16 kalilebih besar. Persamaan laju reaksi tersebut adalah ....

Terdapat suatu reaksi:
 

 
 

Jika kemolaran NO dinaikkan 2 kali dan kemolaran  tetap, laju reaksi 4 kali lebih besar. Jika kemolaran NO dan undefined dinaikkan 2 kali, laju reaksi menjadi 16 kali lebih besar. Persamaan laju reaksi tersebut adalah ....

  1. begin mathsize 14px style italic v equals italic k space open square brackets N O close square brackets squared end style 

  2. begin mathsize 14px style italic v equals italic k italic space open square brackets N O close square brackets open square brackets Br subscript 2 close square brackets cubed end style   

  3. begin mathsize 14px style italic v equals italic k space open square brackets N O close square brackets open square brackets Br subscript 2 close square brackets squared end style    

  4. begin mathsize 14px style italic v equals italic k space open square brackets N O close square brackets cubed open square brackets Br subscript 2 close square brackets end style  

  5. begin mathsize 14px style italic v equals italic k space open square brackets N O close square brackets squared open square brackets Br subscript 2 close square brackets squared end style 

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I. Solichah

Master Teacher

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Pembahasan

Untuk reaksi Persamaan umum laju reaksi : Berdasarkan percobaan yang dilakukan, maka Sehingga, persamaan laju reaksimenjadi . Oleh karena itu, jawaban yang benar adalah E.

Untuk reaksi
 

begin mathsize 14px style 2 N O open parentheses italic g close parentheses space plus space Br subscript 2 open parentheses italic g close parentheses yields 2 N O Br open parentheses italic g close parentheses end style 
 

Persamaan umum laju reaksi :
begin mathsize 14px style v space equals space italic k open square brackets N O close square brackets to the power of x open square brackets Br subscript 2 close square brackets to the power of y end style


Berdasarkan percobaan yang dilakukan, maka

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator v over denominator 4 v end fraction end cell equals cell fraction numerator k open square brackets N O close square brackets to the power of x open square brackets Br subscript 2 close square brackets to the power of y over denominator k left square bracket 2 N O right square bracket to the power of x open square brackets Br subscript 2 close square brackets to the power of y end fraction end cell row cell 1 fourth end cell equals cell open square brackets 1 half close square brackets to the power of x space end cell row cell open square brackets 1 half close square brackets squared end cell equals cell open square brackets 1 half close square brackets to the power of x end cell row x equals 2 end table end style     

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator v over denominator 16 v end fraction end cell equals cell fraction numerator k open square brackets N O close square brackets to the power of x open square brackets Br subscript 2 close square brackets to the power of y over denominator k left square bracket 2 N O right square bracket to the power of x left square bracket 2 Br subscript 2 right square bracket to the power of y end fraction end cell row cell 1 over 16 end cell equals cell open square brackets 1 half close square brackets open square brackets 1 half close square brackets to the power of y end cell row cell 1 over 16 cross times 4 over 1 end cell equals cell open square brackets 1 half close square brackets to the power of y end cell row cell 1 fourth end cell equals cell open square brackets 1 half close square brackets to the power of y end cell row cell open square brackets 1 half close square brackets squared end cell equals cell open square brackets 1 half close square brackets to the power of y end cell row y equals 2 end table end style      
Sehingga, persamaan laju reaksi menjadi begin mathsize 14px style v double bond k open square brackets N O close square brackets squared open square brackets Br subscript 2 close square brackets squared end style  . 

Oleh karena itu, jawaban yang benar adalah E.undefinedundefined

 

 

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Pendahuluan Laju Reaksi

Laju Reaksi, Energi Aktivasi, dan Teori Tumbukan

Penentuan Laju Reaksi Single Experiment

Orde Reaksi Multiexperiment

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