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Tentukan pH larutan dari reaksi asam asam basa ber...

Tentukan pH larutan dari reaksi asam asam basa berikut!


begin mathsize 14px style 100 space ml space H subscript 2 S O subscript 3 left parenthesis italic a italic q right parenthesis space 0 comma 2 space M plus 100 space ml space N H subscript 3 left parenthesis italic a italic q right parenthesis space 0 comma 1 space M end style 

Jawaban:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n space H subscript 2 S O subscript 3 end cell equals cell M cross times V end cell row blank equals cell 0 comma 2 cross times 100 end cell row blank equals cell 20 space mmol end cell end table end style 


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n space N H subscript 3 end cell equals cell M cross times V end cell row blank equals cell 0 comma 1 cross times 100 end cell row blank equals cell 10 space mmol end cell end table end style 


Kemudian hitung jumlah mol yang bereaksi



Terdapat sisa asam. Maka perhitungan pH dapat dihitung dengan :


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row M equals cell fraction numerator mol space sisa over denominator volume space campuran end fraction end cell row blank equals cell fraction numerator 15 space mmol over denominator 200 space ml end fraction end cell row blank equals cell 0 comma 075 space M end cell end table end style 


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell italic a cross times M end cell row blank equals cell 2 cross times 0 comma 075 end cell row blank equals cell 0 comma 15 space M end cell row pH equals cell negative sign log open parentheses H to the power of plus sign close parentheses end cell row blank equals cell negative sign log open parentheses 15 cross times 10 to the power of negative sign 2 end exponent close parentheses end cell row blank equals cell 2 minus sign log open parentheses 15 close parentheses end cell end table end style 


Jadi, pH larutan tersebut adalah 2 - log 15.

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