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Tentukan pH: 0,05 M  jika

Tentukan pH:

0,05 M begin mathsize 14px style H N O subscript 2 end style jika begin mathsize 14px style Ka equals 5 x 10 to the power of negative sign 4 end exponent end style 

Jawaban:

begin mathsize 14px style H N O subscript 2 end style merupakan asam lemah. Berikut adalah rumus pH asam lemah:

begin mathsize 14px style open square brackets H to the power of plus sign close square brackets equals square root of Ka space x space end root M pH equals minus sign log space open square brackets H to the power of plus sign close square brackets end style 

begin mathsize 14px style H N O subscript 2 yields H to the power of plus sign and N O subscript 2 end style 

Apabila begin mathsize 14px style H N O subscript 2 end style mempunyai  konsentrasi 0,05 M maka :

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of left parenthesis 5 x 10 to the power of negative sign 4 end exponent end root right parenthesis x left parenthesis 5 x 10 to the power of negative sign 2 end exponent right parenthesis end cell row blank equals cell square root of 25 x 10 to the power of negative sign 6 end exponent end root end cell row blank equals cell 5 x 10 to the power of negative sign 3 end exponent end cell row pH equals cell negative sign log left parenthesis 5 x 10 to the power of negative sign 3 end exponent right parenthesis end cell row blank equals cell 3 minus sign log space 5 end cell end table end style 

Jadi, pH begin mathsize 14px style H N O subscript 2 end styleadalah 3 - log 5.

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