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Tentukannilai limit berikut! x → 3 4 ​ lim ​ 9 x 2 − 6 x − 8 6 x 2 + x − 12 ​

Tentukan nilai limit berikut!

    

  1. .... 

  2. .... 

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L. Rante

Master Teacher

Mahasiswa/Alumni Universitas Negeri Makassar

Jawaban terverifikasi

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Pembahasan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 4 over 3 of fraction numerator 6 x squared plus x minus 12 over denominator 9 x squared minus 6 x minus 8 end fraction end cell equals cell limit as x rightwards arrow 4 over 3 of fraction numerator open parentheses 3 x minus 4 close parentheses open parentheses 2 x plus 3 close parentheses over denominator open parentheses 3 x minus 4 close parentheses open parentheses 3 x plus 2 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 4 over 3 of fraction numerator 2 x plus 3 over denominator 3 x plus 2 end fraction end cell row blank equals cell fraction numerator 2 open parentheses begin display style 4 over 3 end style close parentheses plus 3 over denominator 3 open parentheses begin display style 4 over 3 end style close parentheses plus 2 end fraction end cell row blank equals cell fraction numerator begin display style 8 over 3 end style plus 3 over denominator 4 plus 2 end fraction end cell row blank equals cell fraction numerator begin display style 17 over 3 end style over denominator 6 end fraction end cell row blank equals cell 17 over 18 end cell end table end style 

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142

Anisyah Ramadhani

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Hasil dari x → − 3 lim ​ x 2 + 4 x + 3 x 4 − 10 x 2 + 9 ​ adalah ....

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