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Tentukan nilai dari : ∫(x2+x3​)dx

Pertanyaan

Tentukan nilai dari :

integral open parentheses straight x squared plus 3 over straight x close parentheses dx

I. Sutiawan

Master Teacher

Mahasiswa/Alumni Universitas Pasundan

Jawaban terverifikasi

Jawaban

 integral open parentheses x squared plus 3 over x close parentheses space d x adalah 1 third x cubed plus 3 space ln open vertical bar x close vertical bar plus C 

Pembahasan

integral open parentheses x squared plus 3 over x close parentheses space d x equals integral open parentheses x squared plus 3 x to the power of negative 1 end exponent close parentheses space d x equals fraction numerator x to the power of 2 plus 1 end exponent over denominator 2 plus 1 end fraction plus 3 space ln space open vertical bar x close vertical bar plus C equals 1 third x cubed plus 3 space ln open vertical bar x close vertical bar plus C

Jadi, integral open parentheses x squared plus 3 over x close parentheses space d x adalah 1 third x cubed plus 3 space ln open vertical bar x close vertical bar plus C 

65

5.0 (3 rating)

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