Roboguru

Pertanyaan

Tentukan nilai dari:

open vertical bar 3 x plus 1 close vertical bar space space jika space straight x less than negative 1 third

E. Nur

Master Teacher

Mahasiswa/Alumni Institut Teknologi Sepuluh Nopember

Jawaban terverifikasi

Jawaban

nilai dari open vertical bar 3 x plus 1 close vertical bar space space jika space straight x less than negative 1 third adalah negative 3 x minus 1.

Pembahasan

Ingat definisi nilai mutlak

open vertical bar f open parentheses x close parentheses close vertical bar equals open curly brackets table attributes columnalign left end attributes row cell f open parentheses x close parentheses space space space space space comma space jika space f open parentheses x close parentheses greater or equal than 0 end cell row cell negative f open parentheses x close parentheses space space comma space jika space f open parentheses x close parentheses less than 0 end cell end table close

Maka

open vertical bar 3 x plus 1 close vertical bar equals open curly brackets table row cell 3 x plus 1 space space space space space space space space space space space space comma space jika space space 3 x plus 1 greater or equal than 0 end cell row cell space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 3 x greater or equal than negative 1 end cell row cell space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space x greater or equal than negative 1 third end cell row cell negative open parentheses 3 x plus 1 close parentheses space space space space space space space comma space jika space space space 3 x plus 1 less than 0 end cell row cell space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 3 x less than negative 1 end cell row cell space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space x less than negative 1 third end cell end table close

Sehingga jika x less than negative 1 third

open vertical bar 3 x plus 1 close vertical bar equals negative open parentheses 3 x plus 1 close parentheses equals negative 3 x minus 1

Dengan demikian nilai dari open vertical bar 3 x plus 1 close vertical bar space space jika space straight x less than negative 1 third adalah negative 3 x minus 1.

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