Iklan

Iklan

Pertanyaan

Tentukan nilai x → 1 lim ​ x − 1 x 2 + 2 x − 3 ​ adalah ....

Tentukan nilai  adalah .... 

  1. ...undefined 

  2. ...undefined 

Iklan

K. Prameswari

Master Teacher

Mahasiswa/Alumni Universitas Gadjah Mada

Jawaban terverifikasi

Jawaban

nilai adalah 4.

nilai begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell stack bold l bold i bold m with bold x bold rightwards arrow bold 1 below end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator bold x to the power of bold 2 bold plus bold 2 bold x bold minus bold 3 over denominator bold x bold minus bold 1 end fraction end cell end table end style adalah 4.space  

Iklan

Pembahasan

Jadi, nilai adalah 4.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 1 of fraction numerator x squared plus 2 x minus 3 over denominator x minus 1 end fraction end cell equals cell limit as x rightwards arrow 1 of fraction numerator left parenthesis x minus 1 right parenthesis left parenthesis x plus 3 right parenthesis over denominator x minus 1 end fraction end cell row blank equals cell limit as x rightwards arrow 1 of left parenthesis x plus 3 right parenthesis end cell row blank equals cell 1 plus 3 end cell row blank equals 4 end table end style

Jadi, nilai begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell stack bold l bold i bold m with bold x bold rightwards arrow bold 1 below end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator bold x to the power of bold 2 bold plus bold 2 bold x bold minus bold 3 over denominator bold x bold minus bold 1 end fraction end cell end table end style adalah 4.space  

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

2

Iklan

Iklan

Pertanyaan serupa

Nilai x → 5 lim ​ 2 x 2 − 13 x + 15 x 2 − x − 20 ​ adalah...

11

4.6

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia