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Tentukan komposisi unsur H, N, dan O dalam senyawa asam nitrat ()! (: , , dan )

Pertanyaan

Tentukan komposisi unsur H, N, dan O dalam senyawa asam nitrat (H N O subscript 3)! (italic A subscript r: H equals 1 space g space mol to the power of negative sign 1 end exponent, N equals 14 space g space mol to the power of negative sign 1 end exponent, dan 0 equals 16 space g space mol to the power of negative sign 1 end exponent)

Pembahasan Soal:

Menentukan italic M subscript r space H N O subscript 3:

table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r space H N O subscript 3 end cell equals cell left parenthesis 1 cross times italic A subscript r space H right parenthesis plus left parenthesis 1 cross times italic A subscript r space N right parenthesis plus left parenthesis 3 cross times italic A subscript r space O right parenthesis end cell row blank equals cell left parenthesis 1 cross times 1 right parenthesis plus left parenthesis 1 cross times 14 right parenthesis plus left parenthesis 3 cross times 16 right parenthesis end cell row blank equals cell 1 plus 14 plus 48 end cell row blank equals cell 63 space g space mol to the power of negative sign 1 end exponent end cell end table 

Menentukan komposisi unsur H, N, dan O dalam senyawa:

table attributes columnalign right center left columnspacing 0px end attributes row cell percent sign H end cell equals cell fraction numerator italic A subscript r space H over denominator italic M subscript r space H N O subscript 3 end fraction cross times 100 percent sign end cell row blank equals cell 1 over 63 cross times 100 percent sign end cell row blank equals cell 1 comma 59 percent sign end cell end table 

table attributes columnalign right center left columnspacing 0px end attributes row cell percent sign N end cell equals cell fraction numerator italic A subscript r space N over denominator italic M subscript r space H N O subscript 3 end fraction cross times 100 percent sign end cell row blank equals cell 14 over 63 cross times 100 percent sign end cell row blank equals cell 22 comma 2 percent sign end cell end table 

table attributes columnalign right center left columnspacing 0px end attributes row cell percent sign O end cell equals cell fraction numerator 3 cross times italic A subscript r space O over denominator italic M subscript r space H N O subscript 3 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 3 cross times 16 over denominator 63 end fraction cross times 100 percent sign end cell row blank equals cell 76 comma 21 percent sign end cell end table 

Jadi, jawaban yang benar komposisi H = 1,59%, N = 22,2%, dan O = 76,21%.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 18 Mei 2021

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