Roboguru

Tentukan keliling segitiga ABC di bawah ini:

Pertanyaan

Tentukan keliling segitiga ABC di bawah ini:undefined 

 

Pembahasan Soal:

Dengan perbandingan sisi segitiga siku-siku dapat ditentukan:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator B C over denominator 2 end fraction end cell equals cell fraction numerator x over denominator square root of 3 end fraction end cell row cell B C end cell equals cell fraction numerator 2 x over denominator square root of 3 end fraction end cell row blank equals cell fraction numerator 2 square root of 3 x over denominator 3 end fraction end cell row cell fraction numerator A C over denominator 2 end fraction end cell equals cell x over 1 end cell row cell A C end cell equals cell 2 x end cell end table end style 

selanjutnya dengan teorema pythagoras diperoleh:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell A B end cell equals cell square root of A C squared plus B C squared end root end cell row blank equals cell square root of open parentheses 2 x close parentheses squared plus open parentheses fraction numerator 2 square root of 3 x over denominator 3 end fraction close parentheses squared end root end cell row blank equals cell square root of 4 x squared plus 4 over 3 x squared end root end cell row blank equals cell square root of 16 over 3 x squared end root end cell row blank equals cell fraction numerator 4 x over denominator square root of 3 end fraction end cell row blank equals cell fraction numerator 4 square root of 3 x over denominator 3 end fraction end cell end table end style 

sehingga diperoleh keliling segitiga tersebut:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row K equals cell A B plus B C plus A C end cell row blank equals cell fraction numerator 4 square root of 3 x over denominator 3 end fraction plus fraction numerator 2 square root of 3 x over denominator 3 end fraction plus 2 x end cell row blank equals cell open parentheses 2 square root of 3 plus 2 close parentheses x end cell end table end style 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 02 Maret 2021

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