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Tentukan himpunan penyelesaian dari setiap pertidaksamaan nilai mutlak di bawah ini. f. ∣∣​2x2−8x−1∣∣​≤9

Pertanyaan

Tentukan himpunan penyelesaian dari setiap pertidaksamaan nilai mutlak di bawah ini.

f. open vertical bar 2 x squared minus 8 x minus 1 close vertical bar less or equal than 9 

I. Sutiawan

Master Teacher

Mahasiswa/Alumni Universitas Pasundan

Jawaban terverifikasi

Jawaban

himpunan penyelesaian pertidaksamaan open vertical bar 2 x squared minus 8 x minus 1 close vertical bar less or equal than 9 adalah negative 1 less or equal than x less or equal than 5 

Pembahasan

table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar 2 x squared minus 8 x minus 1 close vertical bar end cell less or equal than 9 row cell negative 9 end cell less or equal than cell 2 x squared minus 8 x minus 1 less or equal than 9 end cell row cell negative 9 end cell less or equal than cell 2 x squared minus 8 x minus 1 space dan space 2 x squared minus 8 x minus 1 less or equal than 9 end cell row cell negative 2 x squared plus 8 x plus 1 minus 9 end cell less or equal than cell 0 space dan space 2 x squared minus 8 x minus 1 minus 9 less or equal than 0 end cell row cell negative 2 x squared plus 8 x minus 8 end cell less or equal than cell 0 space dan space 2 x squared minus 8 x minus 10 less or equal than 0 end cell row cell 2 x squared minus 8 x plus 8 end cell greater or equal than cell 0 space dan space 2 x squared minus 8 x minus 10 less or equal than 0 end cell row cell x squared minus 4 x plus 4 end cell greater or equal than cell 0 space dan space x squared minus 4 x minus 5 less or equal than 0 end cell row cell left parenthesis x minus 2 right parenthesis squared end cell greater or equal than cell 0 space dan space left parenthesis x plus 1 right parenthesis left parenthesis x minus 5 right parenthesis less or equal than 0 end cell end table

open parentheses negative infinity less than x less than infinity close parentheses space dan space open parentheses negative 1 less or equal than x less or equal than 5 close parentheses minus 1 less or equal than x less or equal than 5

Jadi, himpunan penyelesaian pertidaksamaan open vertical bar 2 x squared minus 8 x minus 1 close vertical bar less or equal than 9 adalah negative 1 less or equal than x less or equal than 5 

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Pertanyaan serupa

Penyelesaian pertidaksamaan ∣∣​x2−x−2∣∣​<4  adalah ...

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Jawaban terverifikasi

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