Pertanyaan

Tentukan himpunan penyelesaian dari persamaan berikut .

Tentukan himpunan penyelesaian dari persamaan berikut $open vertical bar fraction numerator 3 z plus 8 over denominator 2 z minus 3 end fraction close vertical bar equals 4$ .

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

himpunan penyelesaian dari persamaan berikut adalah .

himpunan penyelesaian dari persamaan berikut $open vertical bar fraction numerator 3 z plus 8 over denominator 2 z minus 3 end fraction close vertical bar equals 4$ adalah open curly brackets 4 comma 4 over 11 close curly brackets

open curly brackets 4 comma 4 over 11 close curly brackets

Pembahasan

Ingat: Untuk : Untuk : Jadi, himpunan penyelesaian dari persamaan berikut adalah .

Ingat: $open vertical bar fraction numerator 3 z plus 8 over denominator 2 z minus 3 end fraction close vertical bar equals open curly brackets table attributes columnalign left end attributes row cell fraction numerator 3 z plus 8 over denominator 2 z minus 3 end fraction comma space space jika space fraction numerator 3 z plus 8 over denominator 2 z minus 3 end fraction greater or equal than 0 end cell row cell negative fraction numerator 3 z plus 8 over denominator 2 z minus 3 end fraction comma space space jika space fraction numerator 3 z plus 8 over denominator 2 z minus 3 end fraction less than 0 end cell end table close$

Untuk $fraction numerator 3 z plus 8 over denominator 2 z minus 3 end fraction greater or equal than 0$ :

$table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar fraction numerator 3 z plus 8 over denominator 2 z minus 3 end fraction close vertical bar end cell equals 4 row cell fraction numerator 3 z plus 8 over denominator 2 z minus 3 end fraction end cell equals 4 row cell 3 z plus 8 end cell equals cell 4 open parentheses 2 z minus 3 close parentheses end cell row cell 3 z plus 8 end cell equals cell 8 z minus 12 end cell row cell negative 5 z end cell equals cell negative 20 end cell row z equals cell 4 space open parentheses memenuhi space fraction numerator 3 z plus 8 over denominator 2 z minus 3 end fraction greater or equal than 0 close parentheses space end cell end table$

Untuk $fraction numerator 3 z plus 8 over denominator 2 z minus 3 end fraction less than 0$ :

$table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar fraction numerator 3 z plus 8 over denominator 2 z minus 3 end fraction close vertical bar end cell equals 4 row cell negative fraction numerator 3 z plus 8 over denominator 2 z minus 3 end fraction end cell equals 4 row cell negative left parenthesis 3 z plus 8 right parenthesis end cell equals cell 4 open parentheses 2 z minus 3 close parentheses end cell row cell negative 3 z minus 8 end cell equals cell 8 z minus 12 end cell row cell negative 11 z end cell equals cell negative 4 end cell row z equals cell 4 over 11 space open parentheses memenuhi space fraction numerator 3 z plus 8 over denominator 2 z minus 3 end fraction less than 0 close parentheses space end cell end table$

Jadi, himpunan penyelesaian dari persamaan berikut $open vertical bar fraction numerator 3 z plus 8 over denominator 2 z minus 3 end fraction close vertical bar equals 4$ adalah open curly brackets 4 comma 4 over 11 close curly brackets .