Roboguru
SD

Tentukan hasil operasi hitung bentuk aljabar berikut! c. ​​2aa+5​​​​−​​​4a2a−1​​​​+​​​6a3a−4​​

Pertanyaan

Tentukan hasil operasi hitung bentuk aljabar berikut!

c. table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator a plus 5 over denominator 2 a end fraction end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 2 a minus 1 over denominator 4 a end fraction end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 3 a minus 4 over denominator 6 a end fraction end cell end table

S. Indah

Master Teacher

Mahasiswa/Alumni Universitas Lampung

Jawaban terverifikasi

Pembahasan

Pada operasi penjumlahan pecahan aljabar dengan penyebut berbeda, samakan dahulu penyebutnya kemudian sederhanakan hasilnya.

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator a plus 5 over denominator 2 a end fraction minus fraction numerator 2 a minus 1 over denominator 4 a end fraction plus fraction numerator 3 a minus 4 over denominator 6 a end fraction end cell equals cell fraction numerator 6 open parentheses a plus 5 close parentheses minus 3 open parentheses 2 a minus 1 close parentheses plus 2 open parentheses 3 a minus 4 close parentheses over denominator 12 a end fraction end cell row blank equals cell fraction numerator 6 a plus 30 minus 6 a plus 3 plus 6 a minus 8 over denominator 12 a end fraction end cell row blank equals cell fraction numerator 6 a plus 25 over denominator 12 a end fraction end cell end table

Jadi, hasil operasi hitung dari table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator a plus 5 over denominator 2 a end fraction end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 2 a minus 1 over denominator 4 a end fraction end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 3 a minus 4 over denominator 6 a end fraction end cell end table adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 6 a plus 25 over denominator 12 a end fraction end cell end table.

 

20

0.0 (0 rating)

Pertanyaan serupa

Jika x : y = 3 : 4, maka nilai x−yx​−x2+y2x2​ adalah ...

52

4.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia