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Suatu reaksi: , diperoleh data percobaan laju reaksi     Tentukan orde reaksi, harga tetapan laju reaksi, dan persamaan laju reaksi!

Pertanyaan

Suatu reaksi: begin mathsize 14px style A and B yields C end style, diperoleh data percobaan laju reaksi
 


 

Tentukan orde reaksi, harga tetapan laju reaksi, dan persamaan laju reaksi!undefined 

Pembahasan Soal:

Menentukan orde reaksi

Dimisalkan, persamaan laku reaksi adalah begin mathsize 14px style italic r equals k open square brackets A close square brackets to the power of x open square brackets B close square brackets to the power of y end style. Cara mencari orde reaksi begin mathsize 14px style open square brackets A close square brackets space open parentheses x close parentheses end style adalah dengan memilih konsentrasi B yang sama, yaitu data (1) dan (2).

begin mathsize 14px style italic r subscript italic left parenthesis italic 1 italic right parenthesis end subscript over italic r subscript left parenthesis 2 right parenthesis end subscript equals italic k subscript left parenthesis 1 right parenthesis end subscript over italic k subscript left parenthesis 2 right parenthesis end subscript cross times open square brackets open square brackets A close square brackets subscript left parenthesis 1 right parenthesis end subscript over open square brackets A close square brackets subscript left parenthesis 2 right parenthesis end subscript close square brackets to the power of x cross times open square brackets open square brackets B close square brackets subscript left parenthesis 1 right parenthesis end subscript over open square brackets B close square brackets subscript left parenthesis 2 right parenthesis end subscript close square brackets to the power of y end style , harga begin mathsize 14px style italic k subscript left parenthesis 1 right parenthesis end subscript equals italic k subscript left parenthesis 2 right parenthesis end subscript end style (karena suhu tetap), dan begin mathsize 14px style open square brackets B subscript left parenthesis 1 right parenthesis end subscript close square brackets equals open square brackets B subscript left parenthesis 2 right parenthesis end subscript close square brackets end style sehingga begin mathsize 14px style open square brackets B subscript left parenthesis 1 right parenthesis end subscript over B subscript left parenthesis 2 right parenthesis end subscript close square brackets to the power of italic y end style dapat dihilangkan (bernilai 1).

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 0 comma 015 space Ms to the power of negative sign 1 end exponent over denominator 0 comma 060 space Ms to the power of negative sign 1 end exponent end fraction end cell equals cell left square bracket fraction numerator 0 comma 1 over denominator 0 comma 2 end fraction right square bracket to the power of x cross times left square bracket fraction numerator 0 comma 1 over denominator 0 comma 1 end fraction right square bracket to the power of y end cell row cell 1 fourth end cell equals cell left square bracket 1 half right square bracket to the power of x space end cell row x equals 2 end table end style   

Jadi orde reaksi terhadap A adalah 2. Selanjutnya kita mencari order B, karena konsentrasi A tidak ada yang sama maka kita tetap bisa menggunakan data (1) dan (2) sebagai berikut:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 0 comma 015 space Ms to the power of negative sign 1 end exponent over denominator 0 comma 060 space Ms to the power of negative sign 1 end exponent end fraction end cell equals cell left square bracket fraction numerator 0 comma 1 over denominator 0 comma 2 end fraction right square bracket squared cross times left square bracket fraction numerator 0 comma 1 over denominator 0 comma 1 end fraction right square bracket to the power of y end cell row cell 1 fourth end cell equals cell open square brackets 1 half close square brackets squared cross times open square brackets 1 over 1 close square brackets to the power of y end cell row y equals 1 row blank blank blank end table end style 

Jadi orde reaksi B adalah 1. Orde reaksi total adalah orde reaksi A ditambah orde reaksi B,

 begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell x and y end cell equals cell 2 plus 1 end cell row cell x and y end cell equals 3 end table end style 

Order reaksi total adalah 3.

Menentukan k laju reaksi

Persamaan laju reaksi pembentukkan C dapat dituliskan sebagai berikut.  

begin mathsize 14px style italic r equals italic k open square brackets A close square brackets squared open square brackets B close square brackets to the power of 1 end style 

Untuk penentuan k laju reaksi maka dapat memasukan data percobaan di atas misa pada data nomor (1), maka diperoleh: 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row italic r equals cell italic k italic left square bracket italic A italic right square bracket to the power of italic 2 italic open square brackets B italic close square brackets to the power of italic 1 end cell row cell 0 comma 015 end cell equals cell italic k left square bracket 0 comma 1 right square bracket squared left square bracket 0 comma 1 right square bracket to the power of 1 space end cell row italic k equals cell 0 comma 015 end cell end table end style 

Jadi harga k laju reaksi adalah 0,015.

Dari data di atas maka kita memperoleh persamaan laju reaksi yaitu

begin mathsize 14px style italic r equals 0 comma 015 open square brackets A close square brackets squared open square brackets B close square brackets to the power of 1 end style 

 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 03 April 2021

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