Roboguru

Suatu larutan  sebanyak 0,074 gram mempunyai  dalam 100 mL air.  atom X adalah ....

Pertanyaan

Suatu larutan begin mathsize 14px style X open parentheses O H close parentheses subscript 2 end style sebanyak 0,074 gram mempunyai begin mathsize 14px style K subscript sp equals 4 cross times 10 to the power of negative sign 6 end exponent end style dalam 100 mL air. begin mathsize 14px style A subscript r end style atom X adalah ....begin mathsize 14px style space end style 

Pembahasan Soal:

Error converting from MathML to accessible text. 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp space X open parentheses O H close parentheses subscript 2 end cell equals cell open square brackets X to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared end cell row cell 4 cross times 10 to the power of negative sign 6 end exponent end cell equals cell open parentheses s close parentheses left parenthesis 2 s right parenthesis squared end cell row cell 4 cross times 10 to the power of negative sign 6 end exponent end cell equals cell 4 s cubed end cell row s equals cell cube root of fraction numerator 4 cross times 10 to the power of negative sign 6 end exponent over denominator 4 end fraction end root end cell row s equals cell 10 to the power of negative sign 2 end exponent space M end cell end table end style 


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row s equals cell m over M subscript r cross times fraction numerator 1.000 over denominator V end fraction end cell row cell 10 to the power of negative sign 2 end exponent end cell equals cell fraction numerator 0 comma 074 over denominator M subscript r end fraction cross times fraction numerator 1.000 over denominator 100 end fraction end cell row cell 10 to the power of negative sign 2 end exponent end cell equals cell fraction numerator 0 comma 74 over denominator M subscript r end fraction end cell row cell M subscript r end cell equals cell fraction numerator 0 comma 74 over denominator 10 to the power of negative sign 2 end exponent end fraction end cell row cell M subscript r end cell equals 74 end table end style 


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript r space X open parentheses O H close parentheses subscript 2 end cell equals cell left parenthesis 1 cross times A subscript r space X right parenthesis plus left parenthesis 2 cross times A subscript r space O right parenthesis plus left parenthesis 2 cross times A subscript r space H right parenthesis end cell row 74 equals cell A subscript r space X plus left parenthesis 2 cross times 16 right parenthesis plus left parenthesis 2 cross times 1 right parenthesis end cell row 74 equals cell A subscript r space X plus 34 end cell row cell A subscript r space X end cell equals cell 74 minus sign 34 end cell row cell A subscript r space X end cell equals 40 end table end style 


Jadi, massa atom relatif atom X adalah 40.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 15 Maret 2021

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