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Suatu larutan penyangga yang terdiri atas larutan HCOOH (Ka​=4 ×10−4) dan (HCOO)2​Ca dengan volume yang sama memiliki pH=4−log 6. Perbandingan konsentrasi antara larutan dan  dalam larutan tersebut adalah...

Pertanyaan

Suatu larutan penyangga yang terdiri atas larutan begin mathsize 14px style H C O O H end style begin mathsize 14px style left parenthesis K subscript a equals 4 space cross times 10 to the power of negative sign 4 end exponent right parenthesis end style dan begin mathsize 14px style open parentheses H C O O close parentheses subscript 2 Ca end style dengan volume yang sama memiliki begin mathsize 14px style pH equals 4 minus sign log space 6 end style. Perbandingan konsentrasi antara larutan begin mathsize 14px style H C O O H end style dan begin mathsize 14px style open parentheses H C O O close parentheses subscript 2 Ca end style dalam larutan tersebut adalah...

  1. 1 : 3

  2. 2 : 3

  3. 3 : 1

  4. 3 : 2

  5. 3 : 4

S. Hidayati

Master Teacher

Mahasiswa/Alumni Universitas Indonesia

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah C.undefined 

Pembahasan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell K subscript a cross times fraction numerator open square brackets H C O O H close square brackets over denominator open square brackets H C O O to the power of minus sign close square brackets end fraction end cell row cell 6 cross times 10 to the power of negative sign 4 end exponent end cell equals cell 4 cross times 10 to the power of negative sign 4 end exponent cross times fraction numerator open square brackets H C O O H close square brackets over denominator open square brackets H C O O to the power of minus sign close square brackets end fraction end cell row cell 6 over 4 end cell equals cell fraction numerator open square brackets H C O O H close square brackets over denominator open square brackets H C O O to the power of minus sign close square brackets end fraction end cell row cell 3 over 2 end cell equals cell fraction numerator open square brackets H C O O H close square brackets over denominator open square brackets H C O O to the power of minus sign close square brackets end fraction end cell end table end style 


Perhitungan di atas masih belum menjawab pertanyaan, karena yang ditanyakan perbandingan konsentrasi begin mathsize 14px style H C O O H end style dengan begin mathsize 14px style open parentheses H C O O close parentheses subscript 2 Ca end style. Berdasarkan persamaan ionisasi begin mathsize 14px style open parentheses H C O O close parentheses subscript 2 Ca yields 2 H C O O to the power of minus sign and Ca to the power of 2 plus sign end style, maka


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 3 over 2 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator open square brackets H C O O H close square brackets over denominator open square brackets H C O O to the power of minus sign close square brackets end fraction end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 3 over 2 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator open square brackets H C O O H close square brackets over denominator 2 open square brackets open parentheses H C O O close parentheses subscript 2 Ca close square brackets end fraction end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 3 over 1 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator open square brackets H C O O H close square brackets over denominator open square brackets open parentheses H C O O close parentheses subscript 2 Ca close square brackets end fraction end cell end table end style 


Jadi, jawaban yang benar adalah C.undefined 

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