Roboguru

Suatu kawat dilengkungkan dengan jari-jari R=40 cm...

Suatu kawat dilengkungkan dengan jari-jari R=40 cm dan dialiri arus listrik seperti pada gambar. Diketahui begin mathsize 12px style mu subscript 0 equals 4 straight pi cross times 10 to the power of negative 7 end exponent space Wb. straight m to the power of negative 1 end exponent. straight A to the power of negative 1 end exponent end style, maka induksi magnetik di pusat lengkungan P sebesar ...

  1. 2 comma 5 straight pi cross times 10 to the power of negative 7 end exponent straight T

  2. 5 cross times 10 to the power of negative 7 end exponent straight T

  3. 5 straight pi cross times 10 to the power of negative 7 end exponent straight T

  4. 1 cross times 10 to the power of negative 6 end exponent straight T

  5. straight pi cross times 10 to the power of negative 6 end exponent straight T

Jawaban:

straight a equals space 40 space cm space equals space 4 cross times 10 to the power of negative 1 end exponent straight m

Kawat di atas dilengkungkan hingga membentuk setengah lingkaran. Maka besarnya induksi magnetik di titik P adalah :

straight B equals 1 half cross times fraction numerator straight mu subscript 0 straight I over denominator 2 straight a end fraction  straight B equals 1 half cross times fraction numerator open parentheses 4 straight pi cross times 10 to the power of negative 7 end exponent close parentheses open parentheses 2 close parentheses over denominator open parentheses 2 close parentheses open parentheses 4 cross times 10 to the power of negative 1 end exponent close parentheses end fraction  straight B equals straight pi cross times 10 to the power of negative 6 end exponent straight T

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