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Sistem pada gambar di samping berada dalam keadaan...

Sistem pada gambar di samping berada dalam keadaan seimbang. Besar straight m subscript 1 equals space 60 space kg  dan koefisien gesekan statik antara m subscript 2 space end subscript dan meja adalah 0.2. Massa straight m subscript 2  adalah ....


  1. 2 square root of 2 space kg 

  2. 2 square root of 3 space kg 

  3. 4 space kg 

  4. 4 square root of 2 space kg 

  5. 4 square root of 3 space kg 

Jawaban:

Tinjau dinamika gerak pda sistem m subscript 1 : 

Sistem m subscript 1 space tdak bergerak/keada seimbang maka,

capital sigma F x 1 space equals space 0 space space T subscript 1 space minus space f g e s space equals space 0 space space T subscript 1 space equals space f subscript g e s end subscript space T subscript 1 equals space mu subscript g e s end subscript times N subscript 1 space space T subscript 1 equals space 0 comma 2.60.9 comma 8 space T subscript 1 equals 117 comma 6 space straight N 

Menggunakan  konsep aturan sinus maka tegangan pada masing-masing tali serta massa m subscript 2 dapat ditentukan:

fraction numerator m subscript 2 g over denominator sin space left parenthesis 90 degree space plus space 60 degree right parenthesis end fraction space equals space fraction numerator T subscript 1 over denominator sin space left parenthesis 90 degree space plus space 30 degree right parenthesis space end fraction equals fraction numerator space T subscript 2 over denominator sin space 90 degree end fraction fraction numerator m subscript 2 g over denominator cos space left parenthesis 60 degree right parenthesis end fraction space equals fraction numerator T subscript 1 over denominator cos space left parenthesis 30 degree right parenthesis space end fraction space space m subscript 2 equals fraction numerator cos space left parenthesis 60 degree right parenthesis over denominator cos space left parenthesis 30 degree right parenthesis space end fraction T subscript 1 over g m subscript 2 equals fraction numerator begin display style 1 half end style over denominator begin display style 1 half space square root of 3 end style end fraction fraction numerator 117 comma 6 over denominator 9 comma 8 end fraction m subscript 2 equals fraction numerator begin display style 1 end style over denominator begin display style space square root of 3 end style end fraction cross times 12 m subscript 2 equals fraction numerator begin display style 1 end style over denominator begin display style 3 end style end fraction square root of 3 cross times 12 m subscript 2 equals 4 square root of 3 space kg 


Jadi, jawaban yang benar adalah E.

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