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Pertanyaan

Selesaikan ( 2 3 ​ − 1 0 ​ ) − ( 1 2 ​ 0 1 ​ ) + ( − 1 − 2 ​ − 3 − 4 ​ ) .

Selesaikan .space 

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I. Ridha

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Jawaban

.

 open parentheses table row 2 cell negative 1 end cell row 3 0 end table close parentheses minus open parentheses table row 1 0 row 2 1 end table close parentheses plus open parentheses table row cell negative 1 end cell cell negative 3 end cell row cell negative 2 end cell cell negative 4 end cell end table close parentheses equals open parentheses table row 0 cell negative 4 end cell row cell negative 1 end cell cell negative 5 end cell end table close parentheses.space 

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Pembahasan

Ingat kembali: Dengan demikian, Jadi, .

Ingat kembali:

  • open parentheses table row a b row c d end table close parentheses minus open parentheses table row m n row o p end table close parentheses equals open parentheses table row cell a minus m end cell cell b minus n end cell row cell c minus o end cell cell d minus p end cell end table close parentheses
  • open parentheses table row a b row c d end table close parentheses plus open parentheses table row m n row o p end table close parentheses equals open parentheses table row cell a plus m end cell cell b plus n end cell row cell c plus o end cell cell d plus p end cell end table close parentheses

Dengan demikian, 

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open parentheses table row 2 cell negative 1 end cell row 3 0 end table close parentheses minus open parentheses table row 1 0 row 2 1 end table close parentheses plus open parentheses table row cell negative 1 end cell cell negative 3 end cell row cell negative 2 end cell cell negative 4 end cell end table close parentheses end cell row blank equals cell open parentheses table row cell 2 minus 1 end cell cell negative 1 minus 0 end cell row cell 3 minus 2 end cell cell 0 minus 1 end cell end table close parentheses plus open parentheses table row cell negative 1 end cell cell negative 3 end cell row cell negative 2 end cell cell negative 4 end cell end table close parentheses end cell row blank equals cell open parentheses table row 1 cell negative 1 end cell row 1 cell negative 1 end cell end table close parentheses plus open parentheses table row cell negative 1 end cell cell negative 3 end cell row cell negative 2 end cell cell negative 4 end cell end table close parentheses end cell row blank equals cell open parentheses table row cell 1 plus open parentheses negative 1 close parentheses end cell cell negative 1 plus open parentheses negative 3 close parentheses end cell row cell 1 plus open parentheses negative 2 close parentheses end cell cell negative 1 plus open parentheses negative 4 close parentheses end cell end table close parentheses end cell row blank equals cell open parentheses table row 0 cell negative 4 end cell row cell negative 1 end cell cell negative 5 end cell end table close parentheses end cell end table

Jadi, open parentheses table row 2 cell negative 1 end cell row 3 0 end table close parentheses minus open parentheses table row 1 0 row 2 1 end table close parentheses plus open parentheses table row cell negative 1 end cell cell negative 3 end cell row cell negative 2 end cell cell negative 4 end cell end table close parentheses equals open parentheses table row 0 cell negative 4 end cell row cell negative 1 end cell cell negative 5 end cell end table close parentheses.space 

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Diketahui matriks A = ⎝ ⎛ ​ 3 0 1 ​ − 1 6 5 ​ 2 4 1 ​ ⎠ ⎞ ​ dan matriks B = ⎝ ⎛ ​ − 3 0 1 ​ − 1 6 − 5 ​ 2 4 − 1 ​ ⎠ ⎞ ​ . Tentukan B + A = ....

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