Pertanyaan

Sederhanakanlah. b. 24 m − 4 n − 8 16 m − 6 n 3

Sederhanakanlah.

b. $\frac{16 m ^{- 6} n ^{3}}{24 m ^{- 4} n ^{- 8}}$

Y. Fathoni

Master Teacher

Mahasiswa/Alumni Universitas Negeri Yogyakarta.

Jawaban terverifikasi

Jawaban

diperoleh bentuk sederhananya adalah .

diperoleh bentuk sederhananya adalah $fraction numerator 16 m to the power of negative 6 end exponent space n cubed over denominator 24 m to the power of negative 4 end exponent space n to the power of negative 8 end exponent end fraction equals fraction numerator 2 n to the power of 11 over denominator 3 m squared end fraction$ .

Pembahasan

Ingat kembali konsep bilangan berpangkat. Akan ditentukan bentuk sederhana dari . Jadi, diperoleh bentuk sederhananya adalah .

Ingat kembali konsep bilangan berpangkat.

table attributes columnalign right center left columnspacing 2px 2px 2px end attributes row cell a to the power of m over a to the power of n end cell equals cell a to the power of m minus n end exponent end cell row cell a to the power of negative n end exponent end cell equals cell 1 over a to the power of n end cell end table

Akan ditentukan bentuk sederhana dari $fraction numerator 16 m to the power of negative 6 end exponent space n cubed over denominator 24 m to the power of negative 4 end exponent space n to the power of negative 8 end exponent end fraction$ .

$table attributes columnalign right center left columnspacing 2px end attributes row cell fraction numerator 16 m to the power of negative 6 end exponent space n cubed over denominator 24 m to the power of negative 4 end exponent space n to the power of negative 8 end exponent end fraction end cell equals cell 16 over 24 times m to the power of negative 6 end exponent over m to the power of negative 4 end exponent times n cubed over n to the power of negative 8 end exponent end cell row blank equals cell 2 over 3 times m to the power of negative 6 minus open parentheses negative 4 close parentheses end exponent times n to the power of 3 minus open parentheses negative 8 close parentheses end exponent end cell row blank equals cell 2 over 3 times m to the power of negative 6 plus 4 end exponent times n to the power of 3 plus 8 end exponent end cell row blank equals cell 2 over 3 times m to the power of negative 2 end exponent times n to the power of 11 end cell row blank equals cell 2 over 3 times 1 over m squared times n to the power of 11 end cell row blank equals cell fraction numerator 2 n to the power of 11 over denominator 3 m squared end fraction end cell end table$

Jadi, diperoleh bentuk sederhananya adalah $fraction numerator 16 m to the power of negative 6 end exponent space n cubed over denominator 24 m to the power of negative 4 end exponent space n to the power of negative 8 end exponent end fraction equals fraction numerator 2 n to the power of 11 over denominator 3 m squared end fraction$ .