Roboguru

Sebuah mesin kalor melakukan proses seperti gambar di samping (gas He) AB = isobarik; BC = adiabatis; CA = isokhorik. Jika ,  dan  . Hitunglah kerja pada masing-masing proses!

Pertanyaan

Sebuah mesin kalor melakukan proses seperti gambar di samping (gas He) AB = isobarik; BC = adiabatis; CA = isokhorik. Jika begin mathsize 14px style T subscript A equals 400 space straight K end style, begin mathsize 14px style T subscript B equals 500 space straight K end style dan begin mathsize 14px style T subscript C equals 600 space straight K end style begin mathsize 14px style left parenthesis n equals 10 to the power of negative 3 space end exponent mol right parenthesis end style. Hitunglah kerja pada masing-masing proses!

Pembahasan Soal:

Diketahui :

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell T subscript A end cell equals cell 400 space straight K end cell row cell T subscript B end cell equals cell 500 space straight K end cell row cell T subscript C end cell equals cell 600 space straight K end cell row n equals cell 10 to the power of negative 3 end exponent space mol end cell row R equals cell 8 comma 31 space straight J divided by mol. straight K end cell end table end style 

Ditanya : W ?

Jawab :

  • Proses AB : Isobarik

 begin mathsize 14px style W subscript A B end subscript equals n R increment T W subscript A B end subscript equals n R left parenthesis T subscript B minus T subscript A right parenthesis W subscript A B end subscript equals 10 to the power of negative 3 end exponent cross times 8 comma 31 cross times left parenthesis 500 minus 400 right parenthesis W subscript A B end subscript equals 0 comma 83 space straight J end style 

  • Proses BC : Adiabatik 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell W subscript B C end subscript end cell equals cell negative increment U subscript B C end subscript end cell row cell W subscript B C end subscript end cell equals cell negative 3 over 2 n R left parenthesis T subscript C minus T subscript B right parenthesis end cell row cell W subscript B C end subscript end cell equals cell negative 3 over 2.10 to the power of negative 3 end exponent.8 comma 31 left parenthesis 600 minus 500 right parenthesis end cell row cell W subscript B C end subscript end cell equals cell negative 1 comma 25 space straight J end cell row blank blank blank end table end style 

  • Proses CA : Isokhorik

begin mathsize 14px style W subscript C A end subscript equals 0 space straight J end style 

Dengan demikian , masing-masing proses memiliki Kerja : begin mathsize 14px style bold italic W subscript bold A bold B end subscript bold equals bold 0 bold comma bold 83 bold space bold J bold semicolon bold space bold italic W subscript bold B bold C end subscript bold equals bold minus bold 1 bold comma bold 25 bold space bold J bold semicolon bold space bold italic W subscript bold C bold A end subscript bold equals bold minus bold 0 bold space bold J end style.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 15 Maret 2021

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