Roboguru

Sebuah benda yang berkecepatan 0,6c memiliki energi total . Jika energi c adalah kecepatan cahaya, maka saat benda tersebut berkecepatan 0,8c, energi totalnya menjadi....

Pertanyaan

Sebuah benda yang berkecepatan 0,6c memiliki energi total begin mathsize 14px style open parentheses 1 comma 5 cross times 10 to the power of negative 3 end exponent space gram close parentheses c squared end style. Jika energi c adalah kecepatan cahaya, maka saat benda tersebut berkecepatan 0,8c, energi totalnya menjadi....space

  1. begin mathsize 14px style open parentheses 2 cross times 10 to the power of negative 3 end exponent space gram close parentheses c squared end style 

  2. undefined 

  3. begin mathsize 14px style open parentheses 1 comma 2 cross times 10 to the power of negative 3 end exponent space gram close parentheses c squared end style 

  4. begin mathsize 14px style open parentheses 1 comma 3 cross times 10 to the power of negative 3 end exponent space gram close parentheses c squared end style 

  5. begin mathsize 14px style open parentheses 9 cross times 10 to the power of negative 3 end exponent space gram close parentheses c squared end style 

Pembahasan Soal:

Diketahui :

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 1 end cell equals cell 0 comma 6 c end cell row cell E subscript 1 end cell equals cell open parentheses 1 comma 5 cross times 10 to the power of negative 3 end exponent space gram close parentheses straight c squared end cell row cell v subscript 2 end cell equals cell 0 comma 8 c end cell end table end style 

Ditanya :

begin mathsize 14px style E subscript 2 equals.... ? end style 

Jawab :

Energi total benda yang bergerak :

begin mathsize 14px style E equals m c squared end style 

Kita cari energi diam :

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell E subscript 1 end cell equals cell fraction numerator E subscript o over denominator square root of 1 minus open parentheses begin display style v over c end style close parentheses squared end root end fraction end cell row cell open parentheses 1 comma 5 cross times 10 to the power of negative 3 end exponent space gram close parentheses straight c squared end cell equals cell fraction numerator E subscript o over denominator square root of 1 minus open parentheses begin display style fraction numerator 0 comma 6 c over denominator c end fraction end style close parentheses squared end root end fraction end cell row cell open parentheses 1 comma 5 cross times 10 to the power of negative 3 end exponent space gram close parentheses straight c squared end cell equals cell fraction numerator E subscript o over denominator 0 comma 8 end fraction end cell row cell E subscript o end cell equals cell open parentheses 1 comma 2 cross times 10 to the power of negative 3 end exponent space gram close parentheses straight c squared end cell end table end style 

Energi diam kedua kejadian itu sama, artinya energi total pada kecepatan kedua diperoleh :

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell E subscript 2 end cell equals cell fraction numerator E subscript o over denominator square root of 1 minus open parentheses begin display style v subscript 2 over c end style close parentheses squared end root end fraction end cell row cell E subscript 2 end cell equals cell fraction numerator open parentheses 1 comma 2 cross times 10 to the power of negative 3 end exponent space gram close parentheses straight c squared over denominator square root of 1 minus open parentheses begin display style fraction numerator 0 comma 8 c over denominator c end fraction end style close parentheses squared end root end fraction end cell row cell E subscript 2 end cell equals cell fraction numerator open parentheses 1 comma 2 cross times 10 to the power of negative 3 end exponent space gram close parentheses straight c squared over denominator 0 comma 6 end fraction end cell row cell E subscript 2 end cell equals cell open parentheses 2 cross times 10 to the power of negative 3 end exponent space gram close parentheses straight c squared end cell end table end style 

Jadi, jawaban yang tepat adalah A.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 13 Maret 2021

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved