Pertanyaan

Sebanyak 9 gram glukosa ( M r ​ = 180 g mol − 1 ) dilarutkan dalam 27 garam air pada suhu 3 0 ∘ C . Jika tekananlarutan pada suhu tersebut sebesar 31,04 mmHg, besarnya penurunan tekanan uap jenuh larutan adalah ....

Sebanyak 9 gram glukosa dilarutkan dalam 27 garam air pada suhu . Jika tekanan larutan pada suhu tersebut sebesar 31,04 mmHg, besarnya penurunan tekanan uap jenuh larutan adalah ....

  1. begin mathsize 14px style 5 comma 4 cross times 10 to the power of negative sign 2 end exponent space cmHg end style 

  2. begin mathsize 14px style 9 comma 6 cross times 10 to the power of negative sign 2 end exponent space cmHg end style

  3. begin mathsize 14px style 10 comma 04 cross times 10 to the power of negative sign 2 end exponent space cmHg end style

  4. begin mathsize 14px style 15 comma 20 cross times 10 to the power of negative sign 2 end exponent space cmHg end style

  5. begin mathsize 14px style 20 comma 52 cross times 10 to the power of negative sign 2 end exponent space cmHg end style

Y. Rochmawatie

Master Teacher

Jawaban terverifikasi

Pembahasan

Pembahasan

Penambahan glukosa menyebabkan penurunan terhadap tekanan uap larutan. Menghitung fraksi mol pelarut. Menghitung tekanan uap pelarut murni Menghitung penurunan tekanan uap larutan Berdasarkan uraian perhitungan di atas, maka jawaban yang paling tepat adalah B.

Penambahan glukosa menyebabkan penurunan terhadap tekanan uap larutan.

  • Menghitung fraksi mol pelarut.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell X subscript p end cell equals cell fraction numerator n subscript pelarut over denominator n subscript pelarut and n subscript zat space terlarut end subscript end fraction end cell row cell X subscript p end cell equals cell fraction numerator bevelled fraction numerator m space air over denominator Mr space air end fraction over denominator bevelled fraction numerator m space air over denominator Mr space air end fraction plus bevelled fraction numerator m space glukosa over denominator Mr space glukosa end fraction end fraction end cell row cell X subscript p end cell equals cell fraction numerator bevelled fraction numerator 27 space g over denominator 18 space g middle dot mol to the power of negative sign 1 end exponent end fraction over denominator bevelled fraction numerator 27 space g over denominator 18 space g middle dot mol to the power of negative sign 1 end exponent end fraction plus bevelled fraction numerator 9 space g over denominator 180 space g middle dot mol to the power of negative sign 1 end exponent end fraction end fraction end cell row cell X subscript p end cell equals cell fraction numerator 1 comma 5 space mol over denominator 1 comma 5 space space mol plus 0 comma 05 space mol end fraction end cell row cell italic X subscript italic p end cell bold almost equal to cell bold 0 bold comma bold 968 end cell end table end style 

  • Menghitung tekanan uap pelarut murni

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row P equals cell X subscript p middle dot P to the power of o end cell row cell P to the power of o end cell equals cell P over X subscript p end cell row cell P to the power of o end cell equals cell fraction numerator 31 comma 04 space mmHg over denominator 0 comma 968 end fraction end cell row cell P to the power of italic o end cell bold almost equal to cell bold 32 bold space bold mmHg end cell end table end style   

  • Menghitung penurunan tekanan uap larutan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell increment P end cell equals cell P to the power of o minus sign P end cell row cell increment P end cell equals cell open parentheses 32 minus sign 31 comma 04 close parentheses space mmHg end cell row cell increment P end cell equals cell 0 comma 96 space mmHg end cell row cell increment P end cell equals cell 0 comma 096 space cmHg end cell row cell bold increment P end cell bold equals cell bold 9 bold comma bold 6 bold cross times bold 10 to the power of bold minus sign bold 2 end exponent bold space bold cmHg end cell row blank blank blank row blank blank blank end table end style 

Berdasarkan uraian perhitungan di atas, maka jawaban yang paling tepat adalah B.

 

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