Roboguru

Sebanyak 32 gram kalsium karbida  dilarutkan dalam...

Sebanyak 32 gram kalsium karbida begin mathsize 14px style open parentheses Ca C subscript 2 close parentheses end style dilarutkan dalam air menghasilkan gas asetilena, begin mathsize 14px style C subscript 2 H subscript 2 end style, menurut reaksi:

begin mathsize 14px style Ca C subscript 2 open parentheses s close parentheses and 2 H subscript 2 O open parentheses l close parentheses yields Ca open parentheses O H close parentheses subscript 2 open parentheses s close parentheses and C subscript 2 H subscript 2 open parentheses g close parentheses end style

volume gas asetilena yang terbentuk, di ukur pada begin mathsize 14px style 0 to the power of o C end style, 1 atm adalah ....

Jawaban:

begin mathsize 14px style n subscript Ca C subscript 2 end subscript equals bevelled 32 over 64 equals 0 comma 5 space mol Ca C subscript 2 open parentheses s close parentheses and 2 H subscript 2 O open parentheses l close parentheses yields Ca open parentheses O H close parentheses subscript 2 open parentheses s close parentheses and C subscript 2 H subscript 2 open parentheses g close parentheses 0 comma 5 space space space space space space space space space space space space space space space space tilde bottom enclose negative sign 0 comma 5 space space space space space space space space space space space space space minus sign 1 space space space space space space space space space plus 0 comma 5 space space space space space space space space space space space space space space plus 0 comma 5 end enclose 0 space space space space space space space space space space space space space space space space space space space tilde space space space space space space space space space space space space space space space space 0 comma 5 space space space space space space space space space space space space space space space space space space 0 comma 5  n subscript C subscript 2 H subscript 2 end subscript equals 0 comma 5 space mol V subscript C subscript 2 H subscript 2 end subscript equals 22 comma 4 space cross times space 0 comma 5 space equals 11 comma 2 space L end style

Dengan demikian, maka jawaban yang tepat adalah 11,2 L.

0

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved