Pertanyaan

Sebanyak 3,16 gram ( CH 3 COO ) 2 Ca dilarutkan dalam 500 ml air. Jika K a CH 3 COOH = 5 × 1 0 − 5 ,maka pH larutan tersebut adalah ...(Ar C = 12, H = 1, O= 16, Ca = 40).

Sebanyak 3,16 gram $(CH_{3} COO)_{2} Ca$ dilarutkan dalam 500 ml air. Jika $K_{a} CH_{3} COOH = 5 \times 1 0^{- 5}$ , maka pH larutan tersebut adalah ... (Ar C = 12, H = 1, O = 16, Ca = 40).

4 - log 6
6 – log 4
6 – log 2
8 + log 2
8 + log 4

A. Budi

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

Jawaban terverifikasi

Jawaban

maka jawaban yang tepat adalah E.

Pembahasan

Dengan demikian, maka jawaban yang tepat adalah E.

$begin mathsize 14px style n subscript open parentheses C H subscript 3 C O O close parentheses subscript 2 Ca end subscript equals bevelled fraction numerator 3 comma 16 over denominator 158 end fraction equals 0 comma 02 space mol open parentheses C H subscript 3 C O O close parentheses subscript 2 Ca yields 2 C H subscript 3 C O O to the power of minus sign and Ca to the power of 2 plus sign n subscript C H subscript 3 C O O to the power of minus sign end subscript equals 2 cross times n subscript open parentheses C H subscript 3 C O O close parentheses subscript 2 Ca end subscript n subscript C H subscript 3 C O O to the power of minus sign end subscript equals 0 comma 04 space mol open square brackets C H subscript 3 C O O to the power of minus sign close square brackets equals bevelled fraction numerator 0 comma 04 over denominator 0 comma 5 end fraction equals 0 comma 08 space M C H subscript 3 C O O to the power of minus sign and H subscript 2 O equilibrium C H subscript 3 C O O H and O H to the power of minus sign open square brackets O H to the power of minus sign close square brackets equals square root of K subscript w over K subscript a cross times open square brackets C H subscript 3 C O O to the power of minus sign close square brackets end root open square brackets O H to the power of minus sign close square brackets equals square root of fraction numerator 10 to the power of negative sign 14 end exponent over denominator 5 cross times 10 to the power of negative sign 5 end exponent end fraction cross times 0 comma 08 end root open square brackets O H to the power of minus sign close square brackets equals square root of 16 cross times 10 to the power of negative sign 12 end exponent end root open square brackets O H to the power of minus sign close square brackets equals 4 cross times 10 to the power of negative sign 6 end exponent space M pOH equals minus sign log open square brackets O H to the power of minus sign close square brackets pOH equals minus sign log open parentheses 4 cross times 10 to the power of negative sign 6 end exponent close parentheses pOH equals 6 minus sign log space 4 pH equals 8 plus log space 4 end style$

Dengan demikian, maka jawaban yang tepat adalah E.

Latihan Bab

Konsep Kilat

Pendahuluan Hidrolisis Garam

Hidrolisis Parsial Garam Asam

Hidrolisis Parsial Garam Basa