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Sebanyak 200 mL larutan penyangga mengandung senya...

Sebanyak 200 mL larutan penyangga mengandung senyawa N H subscript 3 dan open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 end subscript masing-masing dengan konsentrasi 0,1 M. Tentukan pH jika pada sistem tersebut ditambahkan 10 mL Na O H 0,1 M! left parenthesis K subscript b space N H subscript 3 equals 1 cross times 10 to the power of negative sign 5 end exponent right parenthesis 

Jawaban:

 

open square brackets O H to the power of minus sign close square brackets double bond K subscript b cross times fraction numerator n subscript b and n subscript b 2 end subscript over denominator n subscript g cross times valensi end fraction open square brackets O H to the power of minus sign close square brackets equals 10 to the power of negative sign 5 end exponent cross times fraction numerator 20 plus 1 over denominator 19 comma 5 cross times 2 end fraction open square brackets O H to the power of minus sign close square brackets equals 10 to the power of negative sign 5 end exponent cross times 21 over 39 open square brackets O H to the power of minus sign close square brackets equals 5 comma 38 cross times 10 to the power of negative sign 6 end exponent  pOH equals minus sign log space open square brackets O H to the power of minus sign close square brackets pOH equals minus sign log space 5 comma 38 cross times 10 to the power of negative sign 6 end exponent pOH equals 6 minus sign log space 5 comma 38  pH equals 14 minus sign pOH pH equals 14 minus sign left parenthesis 6 minus sign log space 5 comma 38 right parenthesis pH equals 8 plus log space 5 comma 38 almost equal to 8 comma 73   
 

Jadi, jawaban sesuai dengan uraian di atas.space  

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