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Sebanyak 11,2 gram kalsium oksida dilarutkan ke dalam air. Larutan ini dapat dinetralkan dengan 25 mL larutan HCl 0,8 M. Kemurnian kalsium oksida tersebut adalah .... (Ar Ca = 40 g/mol, O 16 g/mol,

Sebanyak 11,2 gram kalsium oksida dilarutkan ke dalam air. Larutan ini dapat dinetralkan dengan 25 mL larutan HCl 0,8 M. Kemurnian kalsium oksida tersebut adalah ....  

(Ar Ca = 40 g/mol, O 16 g/mol,  H=1 g/mol, dan Cl=35,5 g/mol) 

Jawaban:

Penentuan persamaan reaksi

begin mathsize 14px style Ca O open parentheses italic s close parentheses and H subscript 2 O open parentheses italic l close parentheses yields Ca open parentheses O H close parentheses subscript 2 left parenthesis italic a italic q right parenthesis end style 

begin mathsize 14px style Ca open parentheses O H close parentheses subscript 2 left parenthesis italic a italic q right parenthesis plus 2 H Cl left parenthesis italic a italic q right parenthesis yields Ca Cl subscript 2 left parenthesis italic a italic q right parenthesis plus 2 H subscript 2 O open parentheses italic l close parentheses end style (sudah setara)

 

Perhitungan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell mol space H Cl end cell equals cell 0 comma 8 space M space x space 0 comma 25 space L equals 0 comma 2 space mol end cell row cell mol space Ca open parentheses O H close parentheses subscript 2 end cell equals cell fraction numerator koefisien space Ca open parentheses O H close parentheses subscript 2 over denominator koefisien space H Cl end fraction x space mol space H Cl end cell row blank equals cell 1 half x 0 comma 2 space mol end cell row blank equals cell 0 comma 1 space mol end cell row cell Mr space Ca open parentheses O H close parentheses subscript 2 end cell equals cell 40 plus left parenthesis 2 x 16 right parenthesis plus left parenthesis 2 x 1 right parenthesis equals 74 space g forward slash mol end cell row cell massa space Ca open parentheses O H close parentheses subscript 2 end cell equals cell 0 comma 1 space mol space x space 74 space g forward slash mol end cell row blank equals cell 7 comma 4 space g end cell end table end style  

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell mr space Ca O end cell equals cell 40 plus 16 equals 56 space g forward slash mol end cell row cell massa space Ca O end cell equals cell fraction numerator Mr space Ca O over denominator Mr space Ca open parentheses O H close parentheses subscript 2 end fraction x space massa space Mr space Ca open parentheses O H close parentheses subscript 2 end cell row blank equals cell fraction numerator 56 space g forward slash mol over denominator 74 space g forward slash mol end fraction x space 7 comma 4 space g end cell row blank equals cell 0 comma 56 space g end cell end table end style

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell percent sign space Ca O end cell equals cell fraction numerator massa space hitungan space over denominator massa space yang space dilarutkan end fraction x 100 space percent sign end cell row blank equals cell fraction numerator 0 comma 56 space g over denominator 11 comma 2 space g end fraction x 100 space percent sign end cell row blank equals cell 5 space percent sign end cell end table end style

 

Jadi, kemurnian kalsium oksida tersebut adalah 5 %.

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