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Sebanyak 100 mL Ca ( NO 3 ​ ) 2 ​ 0,3 M dicampurkan dengan 200 mL larutan NaF 0,06 M. Jika Ksp CaF 2 ​ = 3 , 2 x 1 0 − 11 , maka akan menghasilkan ....

Sebanyak 100 mL  0,3 M dicampurkan dengan 200 mL larutan NaF 0,06 M. Jika  , maka akan menghasilkan ....

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G. Suprobo

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

Jawaban

campuran larutan menghaslilkan endapan .

 campuran larutan menghaslilkan endapan Ca F subscript 2.

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Pembahasan

Penentuan mol: Penentuan konsentrasi ion dan ion Penentuan Qc Membandingkan Qc dengan Kc Jika nilai Qc > Ksp → maka larutan tersebut sudah lewat jenuh ditandai dengan terbentuknya endapan. Dengan demikian,campuran larutan menghaslilkan endapan .

Penentuan mol:

table attributes columnalign right center left columnspacing 0px end attributes row cell mol space Ca open parentheses N O subscript 3 close parentheses subscript 2 end cell equals cell VxM space end cell row blank equals cell 100 space ml space x space 0 comma 3 space M end cell row blank equals cell 30 space mmol end cell row blank blank blank row cell space Ca open parentheses N O subscript 3 close parentheses subscript 2 end cell rightwards harpoon over leftwards harpoon cell space space space space Ca to the power of 2 plus sign space space space space space space plus space space space space space 2 N O subscript 3 to the power of minus sign end cell row blank blank cell 30 space mmol space space space space space space space space space space 30 space mmol space space space space space space space space space space 30 space mmol space space space end cell row blank blank blank row blank blank blank row cell mol space Na F end cell equals VxM row blank equals cell 200 space ml space x space 0 comma 06 space M end cell row blank equals cell 12 space mmol end cell row blank blank blank row cell Na F space space space space space space end cell rightwards harpoon over leftwards harpoon cell space space space space Na to the power of plus sign space space space space plus space space space space F to the power of minus sign end cell row blank blank cell 12 space mmol space space space space space space 12 space mmol space space space space space 12 space mmol space space space space space space space space space space end cell row blank blank blank row blank blank blank end table

Penentuan konsentrasi ion Ca to the power of 2 plus sign dan ion F to the power of minus sign

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets Ca to the power of 2 plus sign close square brackets end cell equals cell fraction numerator mol space Ca to the power of 2 plus sign over denominator Vtotal end fraction end cell row blank equals cell fraction numerator 30 space mmol over denominator 300 space mL end fraction end cell row blank equals cell 0 comma 1 space M end cell row blank blank blank row cell open square brackets F to the power of minus sign close square brackets end cell equals cell fraction numerator mol space F to the power of minus sign over denominator Vtotal end fraction end cell row blank equals cell fraction numerator 12 space mmol over denominator 300 space mL end fraction end cell row blank equals cell 0 comma 04 space M end cell end table

 

Penentuan Qc

table attributes columnalign right center left columnspacing 0px end attributes row cell Qc space Ca F subscript 2 end cell equals cell open square brackets Ca to the power of 2 plus sign close square brackets open square brackets F to the power of minus sign close square brackets squared space equals left parenthesis 10 to the power of negative sign 1 end exponent space M right parenthesis x left parenthesis 4 x 10 to the power of negative sign 2 end exponent space M right parenthesis squared space end cell end tableequals 1 comma 6 x 10 to the power of negative sign 4 end exponent 

Membandingkan Qc dengan Kc

Qc greater than Ksp 1 comma 6 x 10 to the power of negative sign 4 end exponent greater than 3 comma 2 x 10 to the power of negative sign 11 end exponent

Jika nilai Qc > Ksp → maka larutan tersebut sudah lewat jenuh ditandai dengan terbentuknya endapan.

Dengan demikian, campuran larutan menghaslilkan endapan Ca F subscript 2.

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