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Sebanyak 100 mL  0,1 M direaksikan dengan 100 mL  0,1 M, bila , maka pH setelah reaksi adalah...

Pertanyaan

Sebanyak 100 mL begin mathsize 14px style H Cl end style 0,1 M direaksikan dengan 100 mL begin mathsize 14px style N H subscript 4 O H end style 0,1 M, bila begin mathsize 14px style K subscript b space N H subscript 4 O H space adalah space 10 to the power of negative sign 5 end exponent end style, maka pH setelah reaksi adalah...undefined 

Pembahasan Soal:

begin mathsize 14px style mmol space N H subscript 4 O H double bond V space N H subscript 4 O H cross times M space N H subscript 4 O H mmol space N H subscript 4 O H equals 100 space mL cross times 0 comma 1 space mmol forward slash mL mmol space N H subscript 4 O H equals 10 space mmol  mmol space H Cl double bond V space H Cl cross times M space H Cl mmol space H Cl equals 100 space mL cross times 0 comma 1 space mmol forward slash mL mmol space H Cl equals 10 space mmol end style

Karena dalam reaksi didapat koefisien yang sama dan peraksi memiliki mmol yang sama maka yang tersisa adalah garam dan air seperti reaksi berikut.

 

Reaksi hidrolisis garam dan air adalah sebagai berikut.

begin mathsize 14px style N H subscript 4 Cl yields with plus air on top N H subscript 4 to the power of plus sign and Cl to the power of minus sign N H subscript 4 to the power of plus sign and H subscript 2 O equilibrium N H subscript 3 and H to the power of plus sign end style 

Adanya ion undefined dalam hasil reaksi menunjukkan bahwa larutan garam bersifat asam.

begin mathsize 14px style open square brackets H to the power of plus sign close square brackets equals square root of K subscript italic w over K subscript italic b cross times open square brackets garam close square brackets end root open square brackets H to the power of plus sign close square brackets equals square root of K subscript italic w over K subscript italic b cross times open square brackets N H subscript 4 Cl close square brackets end root open square brackets H to the power of plus sign close square brackets equals square root of K subscript italic w over K subscript italic b cross times open square brackets fraction numerator italic n space N H subscript 4 Cl over denominator V space total end fraction close square brackets end root open square brackets H to the power of plus sign close square brackets equals square root of 10 to the power of negative sign 14 end exponent over 10 to the power of negative sign 5 end exponent cross times open square brackets fraction numerator 10 space mmol over denominator 200 space mL end fraction close square brackets end root open square brackets H to the power of plus sign close square brackets equals 7 comma 07 cross times 10 to the power of negative sign 6 end exponent M  pH equals minus sign log open square brackets H to the power of plus sign close square brackets pH equals minus sign log left square bracket 7 comma 07 cross times 10 to the power of negative sign 6 end exponent M right square bracket pH equals 6 minus sign log space 7 comma 07   end style   

Jadi pH  setelah reaksi adalah begin mathsize 14px style bold 6 bold minus sign bold log bold space bold 7 bold comma bold 07 end style.undefined 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 04 April 2021

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