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Sebanyak 10 mL larutan  0,1 M di encerkan dengan m...

Sebanyak 10 mL larutan begin mathsize 14px style C H subscript 3 C O O H end style 0,1 M di encerkan dengan menambah air keladam larutan sampai volume 1 Liter. Tentukan pH larutan sebelum dan sesudah pengenceran begin mathsize 14px style left parenthesis K subscript a space C H subscript 3 C O O H equals 1 cross times 10 to the power of negative sign 5 end exponent right parenthesis end style 

Jawaban:

Senyawa begin mathsize 14px style C H subscript 3 C O O H end style merupakan asam lemah. Untuk menetukan pH dari larutan tersebut maka diperlukan konsentrasi dari ion begin mathsize 14px style H to the power of plus sign end style


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of K subscript a cross times left square bracket Asam space Lemah right square bracket end root end cell row blank equals cell square root of 1 cross times 10 to the power of negative sign 5 end exponent cross times 0 comma 1 end root end cell row blank equals cell square root of 1 cross times 10 to the power of negative sign 6 end exponent end root end cell row blank equals cell 10 to the power of negative sign 3 end exponent end cell row pH equals cell negative sign log space 1 cross times 10 to the power of negative sign 3 end exponent end cell row pH equals 3 end table end style 


Larutan begin mathsize 14px style C H subscript 3 C O O H end style tersebut diencerkan sehingga konsentrasi nya berubah


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript 1 cross times V subscript 1 end cell equals cell M subscript 2 cross times V subscript 2 end cell row cell 0 comma 1 M cross times 10 mL end cell equals cell M subscript 2 cross times 1000 mL end cell row cell M subscript 2 end cell equals cell fraction numerator 0 comma 1 M cross times 10 mL over denominator 1000 mL end fraction end cell row blank equals cell 0 comma 001 M end cell end table end style


Setelah ditentukan konsentrasi setelah pengenceran dapat dicari konsentrasi dari ion begin mathsize 14px style H to the power of plus sign end style


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of 10 to the power of negative sign 5 end exponent cross times 10 to the power of negative sign 3 end exponent end root end cell row blank equals cell square root of 10 to the power of negative sign 8 end exponent end root end cell row blank equals cell 10 to the power of negative sign 4 end exponent end cell row pH equals cell negative sign log space 1 cross times 10 to the power of negative sign 4 end exponent end cell row pH equals 4 row blank blank blank end table end style


Jadi, pH begin mathsize 14px style C H subscript 3 C O O H end style sebelum pengenceran adalah 3 dan sesudah pengenceran adalah 4.space 

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