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pH larutan 100 mL  0,1 M jika Kb  =  adalah...

pH larutan 100 mL begin mathsize 14px style N H subscript 4 Cl end style 0,1 M jika Kb begin mathsize 14px style N H subscript 3 italic left parenthesis italic a italic q italic right parenthesis end style = begin mathsize 14px style 10 to the power of negative sign 5 end exponent end style adalah...

  1. 3undefined

  2. 4undefined

  3. 5undefined

  4. 6undefined

  5. 7undefined

Jawaban:

Perhitungan pH garam asam

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of K subscript w over K subscript b cross times M end root end cell row blank equals cell space square root of 10 to the power of negative sign 14 end exponent over 10 to the power of negative sign 5 end exponent cross times 0 comma 1 end root end cell row blank equals cell space 10 to the power of negative sign 5 end exponent end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell pH space end cell equals cell space minus sign space log space open square brackets H to the power of plus sign close square brackets end cell row blank equals cell space minus sign space log space 10 to the power of negative sign 5 end exponent end cell row blank equals cell space 5 end cell end table end style 

Jadi, jawaban yang benar adalah C.

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