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pH campuran 100 mL larutan  dengan 50 mL larutan  ...

pH campuran 100 mL larutan begin mathsize 14px style C H subscript 3 C O O H space 0 comma 5 space M end style dengan 50 mL larutan begin mathsize 14px style C H subscript 3 C O O Na end style adalah begin mathsize 14px style 5 space minus space log space 9 end style. Tentukan konsentrasi begin mathsize 14px style C H subscript 3 C O O Na end style! begin mathsize 14px style left parenthesis K subscript italic a equals 1 comma 8 cross times 10 to the power of negative sign 5 end exponent right parenthesis end style 

Jawaban:

Konsep yang digunakan untuk menentukan konsentrasi C H subscript 3 C O O Na adalah larutan buffer, berikut adalah alur penyelesaiannya :space 

1. Hitung Konsentrasi C H subscript 3 C O O Na 
M equals fraction numerator mol yields Belum space diketahui over denominator Volume yields 50 space mL end fraction 

2. Menentukan nilai mol dari konsep larutan penyangga asam.

a. Menentukan nilai open square brackets H to the power of plus sign close square brackets dari nilai pHspace 
open square brackets H to the power of plus sign close square brackets space equals space anti space log space pH open square brackets H to the power of plus sign close square brackets space equals space anti space log space left parenthesis space 5 minus sign log space 9 right parenthesis open square brackets H to the power of plus sign close square brackets space equals space 9 cross times 10 to the power of negative sign 5 end exponent

b. menentukan mol C H subscript 3 C O O H  
table attributes columnalign right center left columnspacing 0px end attributes row Mol equals cell M cross times V end cell row blank equals cell 0 comma 5 space cross times 100 space mL end cell row blank equals cell 50 space mmol end cell end table 

c. menentuka mol C H subscript 3 C O O Na
table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell K subscript italic a cross times fraction numerator mol space C H subscript 3 C O O H over denominator mol space C H subscript 3 C O O Na end fraction end cell row cell 9 cross times 10 to the power of negative sign 5 end exponent end cell equals cell 1 comma 8 cross times 10 to the power of negative sign 5 end exponent cross times fraction numerator 50 space mmol over denominator mol space C H subscript 3 C O O Na end fraction end cell row cell mol space C H subscript 3 C O O Na end cell equals cell space 10 space mmol end cell end table 

3. Menentukan konsentrasi begin mathsize 14px style C H subscript 3 C O O Na end style setelah nilai molnya didapatkan.

table attributes columnalign right center left columnspacing 0px end attributes row M equals cell fraction numerator 10 space mmol over denominator 50 space mL end fraction end cell row blank equals cell 0 comma 2 space M end cell end table  

Jadi, jawaban yang tepat adalah 0,2 M.

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