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Perubahan padatan air (es) menjadi uap air melalui tahapan berikut.   Hitung jumlah kalor yang diperlukan untuk mengubah 1 mol es dari  menjadi 1 mol uap air pada  dan tekanan tetap 1 atm. DIketahui kalor jenis air ; dan uap air , kalor peleburan es , serta kalor penguapan air .

Pertanyaan

Perubahan padatan air (es) menjadi uap air melalui tahapan berikut.

H subscript 2 O left parenthesis italic s comma space less than 0 degree C right parenthesis yields H subscript 2 O left parenthesis italic s comma space 0 degree C right parenthesis H subscript 2 O left parenthesis italic s comma space 0 degree C right parenthesis yields H subscript 2 O left parenthesis italic l comma space 0 degree C right parenthesis space space space open parentheses peleburan close parentheses H subscript 2 O left parenthesis italic l comma space 0 degree C right parenthesis yields H subscript 2 O left parenthesis italic l comma space 100 degree C right parenthesis H subscript 2 O left parenthesis italic l comma space 100 degree C right parenthesis yields H subscript 2 O left parenthesis italic g comma space 100 degree C right parenthesis space space open parentheses penguapan close parentheses H subscript 2 O left parenthesis italic g comma space 100 degree C right parenthesis yields H subscript 2 O left parenthesis italic g comma space greater than 100 degree C right parenthesis 

Hitung jumlah kalor yang diperlukan untuk mengubah 1 mol es dari 0 degree C menjadi 1 mol uap air pada 110 degree C dan tekanan tetap 1 atm. DIketahui kalor jenis air equals 4 comma 18 space J space g to the power of negative sign 1 end exponent degree C to the power of negative sign 1 end exponent; dan uap air equals 1 comma 87 space J space g to the power of negative sign 1 end exponent degree C to the power of negative sign 1 end exponent, kalor peleburan es equals 0 comma 33 space kJ space g to the power of negative sign 1 end exponent, serta kalor penguapan air equals 2 comma 26 space kJ space g to the power of negative sign 1 end exponentspace 

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell m space H subscript 2 O end cell equals cell n cross times M subscript r end cell row blank equals cell 1 space mol cross times 18 space g forward slash mol end cell row blank equals cell 18 space g end cell end table 

Tahapan yang dilalui untuk mengubah 1 mol es dari 0 degree C menjadi 1 mol uap air pada 110 degree C:

H subscript 2 O left parenthesis italic s comma space 0 degree C right parenthesis yields H subscript 2 O left parenthesis italic l comma space 0 degree C right parenthesis space space space open parentheses peleburan close parentheses H subscript 2 O left parenthesis italic l comma space 0 degree C right parenthesis yields H subscript 2 O left parenthesis italic l comma space 100 degree C right parenthesis H subscript 2 O left parenthesis italic l comma space 100 degree C right parenthesis yields H subscript 2 O left parenthesis italic g comma space 100 degree C right parenthesis space space open parentheses penguapan close parentheses H subscript 2 O left parenthesis italic g comma space 100 degree C right parenthesis yields H subscript 2 O left parenthesis italic g comma space greater than 100 degree C right parenthesis 

Jumlah kalor yang diperlukan merupakan kalor total dari keempat reaksi.

table attributes columnalign right center left columnspacing 0px end attributes row cell q subscript 1 end cell equals cell m cross times L end cell row blank equals cell 18 space g cross times 0 comma 33 space kJ space g to the power of negative sign 1 end exponent end cell row blank equals cell 5 comma 94 space kJ end cell end table 

table attributes columnalign right center left columnspacing 0px end attributes row cell q subscript 2 end cell equals cell m cross times c subscript air cross times increment T end cell row blank equals cell 18 space g cross times 4 comma 18 space J space g to the power of negative sign 1 end exponent degree C to the power of negative sign 1 end exponent cross times left parenthesis 100 minus sign 0 right parenthesis degree C end cell row blank equals cell 7.524 space J end cell row blank equals cell 7 comma 524 space kJ end cell end table 

table attributes columnalign right center left columnspacing 0px end attributes row cell q subscript 3 end cell equals cell m cross times U end cell row blank equals cell 18 space g cross times 2 comma 26 space kJ space g to the power of negative sign 1 end exponent end cell row blank equals cell 40 comma 68 space kJ end cell end table 

table attributes columnalign right center left columnspacing 0px end attributes row cell q subscript 4 end cell equals cell m cross times c subscript uap cross times increment T end cell row blank equals cell 18 space g cross times 1 comma 87 space J space g to the power of negative sign 1 end exponent degree C to the power of negative sign 1 end exponent cross times left parenthesis 110 minus sign 100 right parenthesis degree C end cell row blank equals cell 336 comma 6 space J end cell row blank equals cell 0 comma 3366 space kJ end cell end table 

table attributes columnalign right center left columnspacing 0px end attributes row q equals cell q subscript 1 and q subscript 2 and q subscript 3 and q subscript 4 end cell row blank equals cell 5 comma 94 space kJ plus 7 comma 524 space kJ plus 40 comma 68 space kJ plus 0 comma 3366 space kJ end cell row blank equals cell 54 comma 58 space kJ end cell end table 


Jadi, kalor yang diperlukan sebesar 54,48 kJ.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 18 Juli 2021

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