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Pertanyaan

Persamaan lingkaran yang berpusat di P (3, -1) dan melalui titik A (5, 2) adalah......

Persamaan lingkaran yang berpusat di P (3, -1) dan melalui titik A (5, 2) adalah......

  1. x squared plus y squared plus 6 x minus 2 y minus 55 equals 0

  2. x squared plus y squared plus 6 x minus 2 y minus 31 equals 0

  3. x squared plus y squared minus 6 x plus 2 y minus 3 equals 0

  4. x squared plus y squared minus 6 x plus 2 y minus 21 equals 0

  5. x squared plus y squared minus 6 x plus 2 y plus 23 equals 0

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N. Mustikowati

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

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Pembahasan

P e r t a m a space – space t a m a space p e r s a m a a n space l i n g k a r a n space d e n g a n space p u s a t space left parenthesis 3 comma negative 1 right parenthesis space d a n space m e l a l u i space t i t i k space A left parenthesis 5 comma 2 right parenthesis space m a k a space j a r i space – space j a r i n y a space a d a l a h  r equals square root of open parentheses x subscript 1 minus x subscript 2 close parentheses squared plus open parentheses y subscript 1 minus y subscript 2 close parentheses squared end root  r equals square root of open parentheses 3 minus 5 close parentheses squared plus open parentheses negative 1 minus 2 close parentheses squared end root  r equals square root of 4 plus 9 end root equals square root of 13  M a k a space p e r s a m a a n space l i n g k a r a n space d e n g a n space p u s a t space left parenthesis 3 comma negative 1 right parenthesis space d a n space b e r j a r i space – space j a r i space square root of 13 space a d a l a h  open parentheses x minus 3 close parentheses squared plus open parentheses y plus 1 close parentheses squared equals open parentheses square root of 13 close parentheses squared  x squared minus 6 x plus 9 plus y squared plus 2 y plus 1 equals 13  x squared plus y squared minus 6 x plus 2 y minus 3 equals 0

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