Roboguru

Persamaan lingkaran yang berpusat di  dan melalui ...

Persamaan lingkaran yang berpusat di begin mathsize 14px style straight P left parenthesis negative 2 comma space 3 right parenthesis end style dan melalui titik begin mathsize 14px style left parenthesis 1 comma space minus 4 right parenthesis end style adalah ... 

  1. ... 

  2. ... 

Jawaban:

Lingaran berpusat di begin mathsize 14px style open parentheses negative 2 comma space 3 close parentheses end style dan melalui titik begin mathsize 14px style open parentheses 1 comma space minus 4 close parentheses end style maka jari-jari lingkaran adalah 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row straight r equals cell square root of open parentheses negative 2 minus 1 close parentheses squared plus open parentheses 3 minus open parentheses negative 4 close parentheses close parentheses squared end root end cell row blank equals cell square root of open parentheses negative 3 close parentheses squared plus open parentheses 7 close parentheses squared end root end cell row blank equals cell square root of 9 plus 49 end root end cell row blank equals cell square root of 58 end cell end table end style 

Sehingga persamaan lingkaran tersebut adalah

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses x minus a close parentheses squared plus open parentheses y minus b close parentheses squared end cell equals cell r squared end cell row cell open parentheses x minus open parentheses negative 2 close parentheses close parentheses squared plus open parentheses y minus 3 close parentheses squared end cell equals cell open parentheses square root of 58 close parentheses squared end cell row cell open parentheses x plus 2 close parentheses squared plus open parentheses y minus 3 close parentheses squared end cell equals cell open parentheses square root of 58 close parentheses squared end cell row cell x squared plus 4 x plus 4 plus y squared minus 6 y plus 9 end cell equals 58 row cell x squared plus y squared plus 4 x minus 6 y minus 45 end cell equals 0 end table end style 

Jadi persamaan lingkaran tersebut adalah begin mathsize 14px style x squared plus y squared plus 4 x minus 6 y minus 45 equals 0 end style

0

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved