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Perhatikan data percobaan berikut: Berdasarkan data di atas, maka rumus persamaan laju dan orde reaksinya adalah...

Perhatikan data percobaan berikut:
 

begin mathsize 14px style P left parenthesis italic a italic q right parenthesis plus Q left parenthesis italic a italic q right parenthesis yields R left parenthesis italic a italic q right parenthesis end style 

 
 

Berdasarkan data di atas, maka rumus persamaan laju dan orde reaksinya adalah...undefined 

  1. begin mathsize 14px style v double bond k space open square brackets P close square brackets semicolon space 2 end style   

  2. begin mathsize 14px style v double bond k space open square brackets P close square brackets open square brackets Q close square brackets semicolon space 2 end style 

  3. begin mathsize 14px style v double bond k space open square brackets P close square brackets open square brackets Q close square brackets squared semicolon space 3 end style 

  4. begin mathsize 14px style v double bond k space open square brackets P close square brackets squared open square brackets Q close square brackets semicolon space 3 end style 

  5. begin mathsize 14px style v double bond k space open square brackets P close square brackets squared open square brackets Q close square brackets squared semicolon space 4 end style 

Jawaban:

Pertama, mencari orde reaksi terlebih dahulu.


begin mathsize 14px style Percobaan space 1 space dan space 2 v subscript 1 over v subscript 2 equals fraction numerator k space open square brackets P subscript 1 close square brackets to the power of x open square brackets Q subscript 1 close square brackets to the power of y over denominator k space open square brackets P subscript 2 close square brackets to the power of x open square brackets Q subscript 2 close square brackets to the power of y end fraction 20 over 40 equals fraction numerator left square bracket 0 comma 1 right square bracket to the power of x left square bracket 0 comma 1 right square bracket to the power of y over denominator left square bracket 0 comma 2 right square bracket to the power of x left square bracket 0 comma 1 right square bracket to the power of y end fraction 1 half equals open square brackets 1 half close square brackets to the power of x x equals 1  Percobaan space 1 space dan space 4 v subscript 1 over v subscript 4 equals fraction numerator k space open square brackets P subscript 1 close square brackets to the power of x open square brackets Q subscript 1 close square brackets to the power of y over denominator k space open square brackets P subscript 4 close square brackets to the power of x open square brackets Q subscript 4 close square brackets to the power of y end fraction 20 over 180 equals fraction numerator left square bracket 0 comma 1 right square bracket to the power of x left square bracket 0 comma 1 right square bracket to the power of y over denominator left square bracket 0 comma 1 right square bracket to the power of x left square bracket 0 comma 3 right square bracket to the power of y end fraction 1 over 9 equals open square brackets 1 third close square brackets to the power of y y equals 2 end style 
 

Orde reaksi totalnya adalah 3 dan persamaan laju reaksinya sebagai berikut:
 

begin mathsize 14px style v double bond k space open square brackets P close square brackets open square brackets Q close square brackets squared end style 
 

Jadi, jawaban yang paling tepat adalah C.undefined 

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