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Pecahan 16 x 4 − 81 6 x 2 + 7 x − 3 ​ disederhanakan menjadi...

Pecahan  disederhanakan menjadi...

  1. fraction numerator 3 x minus 1 over denominator open parentheses 4 x squared plus 9 close parentheses open parentheses 2 x minus 3 close parentheses end fraction

  2. fraction numerator 3 x minus 1 over denominator open parentheses 4 x squared plus 9 close parentheses open parentheses 2 x plus 3 close parentheses end fraction

  3. fraction numerator 3 x plus 1 over denominator open parentheses 4 x squared plus 9 close parentheses open parentheses 2 x minus 3 close parentheses end fraction

  4. fraction numerator 3 x plus 1 over denominator open parentheses 4 x squared plus 9 close parentheses open parentheses 2 x plus 3 close parentheses end fraction

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R. RGFLLIMA

Master Teacher

Jawaban terverifikasi

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Pembahasan

fraction numerator 6 x squared plus 7 x minus 3 over denominator 16 x to the power of 4 minus 81 end fraction  equals fraction numerator open parentheses 3 x minus 1 close parentheses open parentheses 2 x plus 3 close parentheses over denominator open parentheses 4 x squared close parentheses squared minus 9 squared end fraction  equals fraction numerator open parentheses 3 x minus 1 close parentheses open parentheses 2 x plus 3 close parentheses over denominator open parentheses 4 x squared minus 9 close parentheses open parentheses 4 x squared plus 9 close parentheses end fraction  equals fraction numerator open parentheses 3 x minus 1 close parentheses open parentheses 2 x plus 3 close parentheses over denominator open parentheses open parentheses 2 x close parentheses squared minus 3 squared close parentheses open parentheses 4 x squared plus 9 close parentheses end fraction  equals fraction numerator open parentheses 3 x minus 1 close parentheses open parentheses 2 x plus 3 close parentheses over denominator open parentheses 2 x plus 3 close parentheses open parentheses 2 x minus 3 close parentheses open parentheses 4 x squared plus 9 close parentheses end fraction  equals fraction numerator open parentheses 3 x minus 1 close parentheses over denominator open parentheses 2 x minus 3 close parentheses open parentheses 4 x squared plus 9 close parentheses end fraction

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Perhatikan pemfaktoran berikut ini. i. 9 ab + 21 a c = 3 a ( 3 b + 7 c ) ii. x 2 − 9 = ( x − 3 ) ( x − 3 ) iii. 3 p 2 − p − 2 = ( 3 p + 2 ) ( p − 1 ) Pemfaktoran tersebut yang benar adalah...

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