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Pada suhu . Hitunglah kelarutan  pada larutan !

Pertanyaan

Pada suhu begin mathsize 14px style 25 degree C comma space K subscript sp space Ni open parentheses O H close parentheses subscript 2 equals 6 cross times 10 to the power of negative sign 18 end exponent end style. Hitunglah kelarutan begin mathsize 14px style Ni bold open parentheses O H bold close parentheses subscript bold 2 end style pada larutan begin mathsize 14px style Ni Cl subscript bold 2 bold space bold 0 bold comma bold 001 bold space italic M end style!undefined 

Pembahasan Soal:

begin mathsize 14px style Larutan space space space space space space space space space Ni Cl subscript 2 open parentheses aq close parentheses equilibrium Ni to the power of 2 plus sign open parentheses aq close parentheses and 2 Cl to the power of minus sign open parentheses aq close parentheses space space space space space space space space space space space space space space space space space space space space space 0 comma 001 space M space space space space space 0 comma 001 space M space space space space 0 comma 002 space M end style 

Konsentrasi begin mathsize 14px style Ni to the power of 2 plus sign end style dalam larutan merupakan konsentrasi awal. Kemudian, ke dalam larutan ditambahkan begin mathsize 14px style Ni open parentheses O H close parentheses subscript 2 end style. Jika yang terlarut adalah x maka

 

Pada keadaan setimbang, konsentrasi begin mathsize 14px style open square brackets Ni to the power of 2 plus sign close square brackets equals left parenthesis 0 comma 001 plus italic x right parenthesis end style M. Harga x kecil sekali sehingga dapat diabaikan, konsentrasi undefined menjadi 0,001 M. 

begin mathsize 14px style K subscript italic s italic p space end subscript Ni open parentheses O H close parentheses subscript 2 equals open square brackets Ni to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared K subscript italic s italic p space end subscript Ni open parentheses O H close parentheses subscript 2 equals left parenthesis 0 comma 001 right parenthesis cross times left parenthesis 4 x squared right parenthesis 6 cross times 10 to the power of negative sign 18 end exponent equals 0 comma 004 x squared x squared equals fraction numerator 6 cross times 10 to the power of negative sign 18 end exponent over denominator 4 cross times 10 to the power of negative sign 3 end exponent end fraction x equals square root of fraction numerator 6 cross times 10 to the power of negative sign 18 end exponent over denominator 4 cross times 10 to the power of negative sign 3 end exponent end fraction end root x equals 3 comma 87 cross times 10 to the power of negative sign 8 end exponent space M end style  

Jadi kelarutan begin mathsize 14px style Ni bold open parentheses O H bold close parentheses subscript bold 2 end style dalam larutan begin mathsize 14px style Ni Cl subscript bold 2 end style 0,001 M adalah begin mathsize 14px style bold 3 bold comma bold 87 bold cross times bold 10 to the power of bold minus sign bold 8 end exponent bold space italic M end style.space 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 04 April 2021

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