Roboguru

Pada suatu batang baja sepanjang 2 m meramat suatu...

Pada suatu batang baja sepanjang 2 m meramat suatu gelombang bunyi. Gelombang tersebut membutuhkan waktu 0,0002 s untuk mencapai ujung batang dari ujung lainnya. Jika modulus elastistas dari batang baja tersebut sebesar 1 cross times 10 to the power of 10 space Pa, berapa massa jenis baja tersebut?space

Jawaban:

Diketahui :

table attributes columnalign right center left columnspacing 0px end attributes row calligraphic l equals cell 2 space straight m end cell row t equals cell 0 comma 0002 space straight s end cell row E equals cell 1 cross times 10 to the power of 10 space Pa end cell end table 

Ditanya :

Massa jenis baja open parentheses rho close parentheses?

Jawab :

Kita gunakan rumus cepat rambat bunyi pada medium zat padat, dirumuskan :

table attributes columnalign right center left columnspacing 0px end attributes row v equals cell square root of E over rho end root end cell row cell calligraphic l over t end cell equals cell square root of E over rho end root end cell row cell fraction numerator 2 over denominator 0 comma 0002 end fraction end cell equals cell square root of fraction numerator 1 cross times 10 to the power of 10 over denominator rho end fraction end root end cell row cell 10 to the power of 4 end cell equals cell square root of fraction numerator 1 cross times 10 to the power of 10 over denominator rho end fraction end root end cell row cell open parentheses 10 to the power of 4 close parentheses squared end cell equals cell fraction numerator 1 cross times 10 to the power of 10 over denominator rho end fraction end cell row cell 10 to the power of 8 end cell equals cell fraction numerator 1 cross times 10 to the power of 10 over denominator rho end fraction end cell row rho equals cell fraction numerator 1 cross times 10 to the power of 10 over denominator 10 to the power of 8 end fraction end cell row rho equals cell 100 space kg divided by straight m cubed end cell end table 

Jadi, massa jenis baja sebesar bold 100 bold space bold kg bold divided by bold m to the power of bold 3.

0

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved