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Pada reaksi redoks:   koefisien reaksi setara pa...

Pada reaksi redoks:

aMnO subscript 4 to the power of minus sign plus Fe to the power of 2 plus sign and bH to the power of plus sign yields cMn to the power of 2 plus sign and dFe to the power of 3 plus sign and H subscript 2 O 

koefisien reaksi setara pada a, b, c, dan d berturut-turut adalah ….

  1. 1, 4, 1, dan 2space 

  2. 2, 1, 2, dan 4space 

  3. 1, 8, 1, dan 5space 

  4. 2, 8, 2, dan 4space 

  5. 1, 4, 2, dan 2space 

Jawaban:

Persamaan reaksi redoks tersebut dapat disetarakan menggunakan metode perubahan biloks dengan langkah - langkah sebagai berikut:

1. Menentukan unsur yang mengalami perubahan billoks.
space Mn O subscript 4 to the power of minus sign plus Fe to the power of 2 plus sign and H to the power of plus sign yields Mn to the power of 2 plus sign and Fe to the power of 3 plus sign and H subscript 2 O plus 7 space space space space space space space space space space plus 2 space space space space space space space space space space space space space space space plus 2 space space space space space space space plus 3 

Mn mengalami perubahan biloks = 5
Fe mengalami perubahan biloks = 1

2. Menyamakan kedua perubahan biloks.

Mn O subscript 4 to the power of minus sign space dan space Mn to the power of 2 plus sign dikali 1
Fe to the power of 2 plus sign dan space Fe to the power of 3 plus sign dikali 5

Sehingga menjadi:
Mn O subscript 4 to the power of minus sign plus 5 Fe to the power of 2 plus sign and H to the power of plus sign yields Mn to the power of 2 plus sign and 5 Fe to the power of 3 plus sign and H subscript 2 O 

4. Menyetarakan atom O pada ruas kanan dan kiri dengan menambahkan H subscript 2 O.
Mn O subscript 4 to the power of minus sign plus 5 Fe to the power of 2 plus sign and H to the power of plus sign yields Mn to the power of 2 plus sign and 5 Fe to the power of 3 plus sign and 4 H subscript 2 O 

5. Menyetarakan jumlah atom H pada ruas kanan dan kiri dengan menambahkan H to the power of plus sign.
Mn O subscript 4 to the power of minus sign plus 5 Fe to the power of 2 plus sign and 8 H to the power of plus sign yields Mn to the power of 2 plus sign and 5 Fe to the power of 3 plus sign and H subscript 2 O 

Jadi, persamaan reaksi setaranya yaitu:
Mn O subscript 4 to the power of minus sign plus 5 Fe to the power of 2 plus sign and 8 H to the power of plus sign yields Mn to the power of 2 plus sign and 5 Fe to the power of 3 plus sign and H subscript 2 O

Koefisien a, b, c, dan d yaitu 1,8,1, dan 5.

Jadi, jawaban yang benar adalah C.

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