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Nilai  yang memenuhi pertidaksamaan  adalah....

Nilai undefined yang memenuhi pertidaksamaan begin mathsize 14px style square root of x plus 2 end root greater than x end style adalah....undefined 

  1. begin mathsize 14px style negative 2 less or equal than x less than 2 end style 

  2. size 14px minus size 14px 2 size 14px less or equal than size 14px x size 14px less than size 14px 1 

  3. size 14px minus size 14px 1 size 14px less than size 14px x size 14px less than size 14px 2 

  4. begin mathsize 14px style x greater than 2 end style 

  5. begin mathsize 14px style x less than negative 1 space atau space x greater than 2 end style 

Jawaban:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell square root of x plus 2 end root end cell greater than cell x space space space space kuadratkan space kedua space ruas end cell row cell straight x plus 2 end cell greater than cell straight x squared end cell row 0 greater than cell straight x squared minus straight x minus 2 end cell row 0 greater than cell open parentheses straight x minus 2 close parentheses open parentheses straight x plus 1 close parentheses end cell row blank blank cell Angka minus angka space batas space space colon end cell row cell straight x minus 2 end cell equals 0 row straight x equals 2 row cell straight x plus 1 end cell equals 0 row straight x equals cell negative 1 end cell row blank blank blank row blank blank cell Syarat space lain space colon end cell row cell square root of straight x plus 2 end root end cell greater or equal than 0 row cell straight x plus 2 end cell greater or equal than 0 row straight x greater or equal than cell negative 2 end cell row blank blank blank end table end style 

 

Daerah penyelesaian :

 

Jadi daerah penyelesaiannya :

begin mathsize 14px style negative 1 less than x less than 2 end style 

Jadi jawaban yang tepat adalah  C

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