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Pertanyaan

Nilai x yangmemenuhi 3 1 ​ lo g ( x + 3 ​ ) + 3 1 ​ lo g ( x − 3 ​ ) > 0 adalah...

Nilai  yang memenuhi  adalah...

  1. x less than negative square root of 3 atau 0 less than x less than 2 

  2. negative 2 less than x less than negative square root of 3 atau square root of 3 less than x less than 2 

  3. square root of 3 less than x less than 2 

  4. negative 2 less than x less than 2 

  5. negative 3 less than x less than 2 

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R. Hajrianti

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah C.

jawaban yang benar adalah C.

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Pembahasan

Ingat sifat logaritma Ingat sifat logaritma! Sehingga, Menentukan daerah penyelesaian Syarat: Untuk , jika maka: Untuk , jika maka: Untuk , jika maka: Jadi, nilai x yang memenuhi pertidaksamaan di atas adalah . Oleh karena itu, jawaban yang benar adalah C.

log presuperscript 1 third end presuperscript space open parentheses x plus square root of 3 close parentheses plus log presuperscript 1 third end presuperscript space open parentheses x minus square root of 3 close parentheses greater than 0  

Ingat sifat logaritma

log presuperscript a space b plus log presuperscript a space c equals log presuperscript a space b c 

table attributes columnalign right center left columnspacing 0px end attributes row cell log presuperscript 1 third end presuperscript space open parentheses x plus square root of 3 close parentheses plus log presuperscript 1 third end presuperscript space open parentheses x minus square root of 3 close parentheses end cell greater than 0 row cell log presuperscript 1 third end presuperscript space open parentheses x plus square root of 3 close parentheses open parentheses x minus square root of 3 close parentheses end cell greater than 0 row cell log presuperscript 1 third end presuperscript space open parentheses x squared minus 3 close parentheses end cell greater than 0 end table 

Ingat sifat logaritma!

log presuperscript a space 1 equals 0 rightwards double arrow a to the power of 0 equals 1 

Sehingga,

table attributes columnalign right center left columnspacing 0px end attributes row cell log presuperscript 1 third end presuperscript space open parentheses x squared minus 3 close parentheses end cell greater than 0 row cell log presuperscript 1 third end presuperscript space open parentheses x squared minus 3 close parentheses end cell greater than cell log presuperscript 1 third end presuperscript space 1 end cell row cell x squared minus 3 end cell greater than 1 row cell x squared minus 3 minus 1 end cell greater than 0 row cell x squared minus 4 end cell greater than 0 row cell open parentheses x plus 2 close parentheses open parentheses x minus 2 close parentheses end cell greater than 0 row cell x plus 2 end cell greater than 0 row x greater than cell negative 2 end cell row cell x minus 2 end cell greater than 0 row x greater than 2 end table 

Menentukan daerah penyelesaian

 

Syarat:

table attributes columnalign right center left columnspacing 0px end attributes row cell x plus square root of 3 end cell greater than 0 row x greater than cell negative square root of 3 space open parentheses positif close parentheses end cell row cell x minus square root of 3 end cell greater than 0 row x greater than cell square root of 3 space open parentheses positif close parentheses end cell end table  

Untuk negative 2 less than x less than 2, jika x equals 0 maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell x squared minus 4 end cell less than 0 row cell open parentheses negative 1 close parentheses squared minus 4 end cell less than 0 row cell 1 minus 4 end cell less than 0 row cell negative 3 end cell less than cell 0 space open parentheses negatif close parentheses end cell end table 

Untuk x less than negative 2, jika x equals negative 3 maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell x squared minus 4 end cell greater than 0 row cell open parentheses negative 3 close parentheses squared minus 4 end cell greater than 0 row cell 9 minus 4 end cell greater than 0 row 5 greater than cell 0 space open parentheses positif close parentheses end cell end table  

Untuk x greater than 2, jika x equals 3 maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell x squared minus 4 end cell greater than 0 row cell 3 squared minus 4 end cell greater than 0 row cell 9 minus 4 end cell greater than 0 row 5 greater than cell 0 space open parentheses positif close parentheses end cell end table  

Jadi, nilai x yang memenuhi pertidaksamaan di atas adalah square root of 3 less than x less than 2.

Oleh karena itu, jawaban yang benar adalah C.

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