Pertanyaan

Nilai dari sin 24 0 ∘ − sin 15 0 ∘ cos 30 0 ∘ − cos 15 0 ∘ = ...

Nilai dari $\frac{cos 30 0 ^{\circ} - cos 15 0 ^{\circ}}{sin 24 0 ^{\circ} - sin 15 0 ^{\circ}} = ...$

S. Nur

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah A.

Pembahasan

Dengan demikian, jawaban yang tepat adalah A.

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator cos space 300 degree minus cos space 150 degree over denominator sin space 240 degree minus sin space 150 degree end fraction end cell row blank equals cell fraction numerator cos space open parentheses 360 degree minus 60 degree close parentheses minus open parentheses negative cos space open parentheses 180 degree minus 30 degree close parentheses close parentheses over denominator left parenthesis negative sin space open parentheses 180 degree plus 60 degree close parentheses right parenthesis minus sin space left parenthesis 180 degree minus 30 degree right parenthesis end fraction end cell row blank equals cell fraction numerator cos space 60 degree plus cos space 30 degree over denominator negative sin space 60 degree minus sin space 30 degree end fraction end cell row blank equals cell fraction numerator 1 half plus 1 half square root of 3 over denominator negative 1 half square root of 3 minus 1 half end fraction cross times open parentheses 2 over 2 close parentheses end cell row blank equals cell fraction numerator 1 plus square root of 3 over denominator negative square root of 3 minus 1 end fraction cross times fraction numerator negative square root of 3 plus 1 over denominator negative square root of 3 plus 1 end fraction end cell row blank equals cell fraction numerator negative square root of 3 plus 1 minus 3 plus square root of 3 over denominator 3 minus 1 end fraction end cell row blank equals cell negative 2 over 2 end cell row blank equals cell negative 1 end cell end table end style$

Dengan demikian, jawaban yang tepat adalah A.