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Nilai dari cos1680−cos1020sin780−sin120​=...

Pertanyaan

Nilai dari fraction numerator sin invisible function application 78 to the power of 0 minus sin invisible function application 12 to the power of 0 over denominator cos invisible function application 168 to the power of 0 minus cos invisible function application 102 to the power of 0 end fraction equals...

  1. -1

  2. negative 1 half square root of 2

  3. 0

  4. 1 half square root of 2

  5. 1

Pembahasan:

R u m u s space p e n j u m l a h a n space d a n space p e n g u r a n g a n space t r i g o n o m e t r i  A right parenthesis space sin invisible function application a minus sin invisible function application b equals 2 cos invisible function application open parentheses fraction numerator a plus b over denominator 2 end fraction close parentheses sin invisible function application open parentheses fraction numerator a minus b over denominator 2 end fraction close parentheses  B right parenthesis space cos invisible function application a minus cos invisible function application b equals negative 2 sin invisible function application open parentheses fraction numerator a plus b over denominator 2 end fraction close parentheses sin invisible function application open parentheses fraction numerator a minus b over denominator 2 end fraction close parentheses  K e d u a space r u m u s space d i a t a s space a k a n space d i p a k a i space d a l a m space m e n j a w a b space s o a l  fraction numerator sin invisible function application 78 to the power of 0 minus sin invisible function application 12 to the power of 0 over denominator cos invisible function application 168 to the power of 0 minus cos invisible function application 102 to the power of 0 end fraction equals fraction numerator 2 cos invisible function application open parentheses fraction numerator 78 plus 12 over denominator 2 end fraction close parentheses sin invisible function application open parentheses fraction numerator 78 minus 12 over denominator 2 end fraction close parentheses over denominator negative 2 sin invisible function application open parentheses fraction numerator 168 plus 102 over denominator 2 end fraction close parentheses sin invisible function application open parentheses fraction numerator 168 minus 102 over denominator 2 end fraction close parentheses end fraction  space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 2 cos invisible function application open parentheses 45 close parentheses sin invisible function application open parentheses 33 close parentheses over denominator negative 2 sin invisible function application open parentheses 135 close parentheses sin invisible function application open parentheses 33 close parentheses end fraction  space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 2 cos invisible function application open parentheses 45 close parentheses horizontal strike sin invisible function application open parentheses 33 close parentheses end strike over denominator negative 2 sin invisible function application open parentheses 135 close parentheses horizontal strike sin invisible function application open parentheses 33 close parentheses end strike end fraction  space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 2 times 1 half square root of 2 over denominator negative 2 times 1 half square root of 2 end fraction  space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals negative 1 space left parenthesis A right parenthesis

Jawaban terverifikasi

Dijawab oleh:

I. Roy

Mahasiswa/Alumni Universitas Negeri Surabaya

Terakhir diupdate 04 Oktober 2021

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